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adell [148]
3 years ago
11

△DEF is reflected to form​​ ​ △D′E′F′ ​. The vertices of ​ ​ △DEF ​ ​ are ​ D(−1,−1) ​ , ​ E′(1,−1) ​ , and ​ F(−1,−6) ​ . The v

ertices of ​ △P′Q′R′ ​ are D′(−1,1) , E′(1,1) , and F′(−1,6) . Which reflection results in the transformation of ​ ​ ​ △DEF ​ ​ ​​ to ​ ​ ​ △D′E′F′ ​ ​ ​​? reflection across the x-axis reflection across the y-axis reflection across y = x reflection across y=−x

Mathematics
2 answers:
tia_tia [17]3 years ago
5 0

Answer:

Triangle DEF is reflected across x -axis.

Step-by-step explanation:

Since, the rule of reflection across x -axis,

(x,y)\rightarrow (x,-y)

The rule of reflection across y -axis,

(x,y)\rightarrow (-x,y)

The rule of reflection across line y = x,

(x,y)\rightarrow (y,x)

The rule of reflection across y = -x ,

(x,y)\rightarrow (-y,-x)

Since, in transformation of the triangle DEF with vertices D(-1,-1) , ​E(1,-1) and ​ F(-1,-6) into the triangle D′E′F' with vertices D′(-1,1) , E′(1,1) , and F′(-1,6).

The rule of reflection is,

(x,y)\rightarrow (x,-y)

Thus, the triangle DEF is reflected across x -axis.

bekas [8.4K]3 years ago
3 0

Reflection across the x-axis because all y-coordinates for triangle DEF are the opposite for the y-coordinates in triangle D'E'F'.

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<u />

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