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rewona [7]
2 years ago
15

Write 15 as a product of prime numbere

Mathematics
2 answers:
fenix001 [56]2 years ago
7 0
Maybe 10 or something i dont know im only 10 so i cant really answer that i just need points
pentagon [3]2 years ago
4 0

15 = 5*3   both 5 and 3 are prime numbers since the only numbers that go into 5 and 3 are 1  and themselves so 15 as a product of prime numbers is 5*3

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80 is 5% of what number?​
nikklg [1K]

Answer:

1600

Step-by-step explanation:

1600 x 0.05 = 80

or

80 / .05 = 1600

3 0
2 years ago
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4 math problem
Aneli [31]

Answer:

Step-by-step explanation:

1)y=-6x-14   ---------(i)

-x-3y=-9  ---------- (ii)

Substitution method:

Substitute y  value in equ (i)

-x -3*(-6x-14) = -9

-x - 3*-6x -3*(-14)= -9

-x + 18x + 42 = -9

17x = -9 -42

17x = -51

x = -51/17

x = -3

Substitute x value in equation (i)

y = -6*-3 -14

y =18-14

y = 4

6 0
3 years ago
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HELP ITS HARD PLZZZ need help to 1 throw 6
Nata [24]
Ok so here's a trick king Henry doesn't usually drink chocolate milk or king Henry dabs under dogs calling mom and here's what it will look like the pic and then u have to convert them so 8 liters converting into blank dL so u put a x over the letter L and u don't see that. u see the big U well that means gram liter and meter so u put a x over top of that and now u want to go to the d so now u go just to the d NOT da and ur gonna scoop when ur done scooping them u put a dot where u ended on top of that letter now u get ur first number or what one u started with so I did 8L so I get 8 and since there is no decimal u put it at the end and now I'll scoop and since ur getting smaller u move the decimal to the left (cause left is less) and u get .8 and that's how u do that if u need help with the other ones just let me know and I'll help u

3 0
2 years ago
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I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
What matrix results from −8·A?
djverab [1.8K]
Is that all the question says can you give it into more details


So I can help you out
3 0
2 years ago
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