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rewona [7]
3 years ago
15

Write 15 as a product of prime numbere

Mathematics
2 answers:
fenix001 [56]3 years ago
7 0
Maybe 10 or something i dont know im only 10 so i cant really answer that i just need points
pentagon [3]3 years ago
4 0

15 = 5*3   both 5 and 3 are prime numbers since the only numbers that go into 5 and 3 are 1  and themselves so 15 as a product of prime numbers is 5*3

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Find the exact length of the curve.<br> x = 5 + 9t2, y = 4 + 6t3, 0 ≤ t ≤ 3
kodGreya [7K]

The exact length of the curve given the following system of inequalities is ≈ 1637.

<h3>What is a system of inequalities?</h3>

A system of inequalities refers to a set of two or more inequalities with one or more variables. This kind of system is used when a problem needs a range of solutions a there is over one constraint.

<h3>What is the length of the curve with the above system of inequalities?</h3>

Step One - Let's restate the equations

We have:

x = 5 + 9t²

y = 4 + 6t³

Where

0 ≤ t ≤ 3

Step 2 - Differentiate them

The first derivative of dx/dt

= d/dt [9t² + 5)

= 9 * (d/dt) (t²) + (d/dt) (5)

= 9.2t + 0

= 18t

Also differentiate (dy/dt)

= d/dt [6t² + 4]

= 6 * (d/dt) [t³] + (d/dt) [4]

= 6.3 t² + 0

= 18t²

To find the length of the arc:

L = \[ \int_{0}^{4} \sqrt{(\frac{dx}{dt})^{2}  + (\frac{dy}{dt})^{2}  dt }

We can thus deduce that:

= \[ \int_{0}^{4} \sqrt{(\fra18t)^{2}  + ({18t^{2} )^{2} dt }

= \int_{0}^{4}[18t \sqrt{1 + {18t^{2} ]

Compute the definite integral and factor out the constraints and we have:

dt = 4912/3

≈ 1,637.3

Hence the exact length of the curve is

≈ 1637

Learn more about the system of inequalities at:
brainly.com/question/9774970
#SPJ1

3 0
2 years ago
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