The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
#SPJ4
$4.25 + $1.50 = $5.75= 2 miles
10 x $1.50 = $15.00=10 miles
10 + 2 = 12 miles
$5.75 + $15.00 = $20.75
U = -b + 21 . . . (1)
u = -2b + 30 . . . (2)
Equating (1) and (2),
-b + 21 = -2b + 30
-b + 2b = 30 - 21
b = 9
u = -9 + 21 = 12
Therefore, (b, u) = (9, 12).
Answer:
Step-by-step explanation:
Given that cards are drawn from a standard 52-card deck until the third club is drawn.
With replacement:
Drawing 3 club prob = 1/52 and non club = 51/52
a) Hence Prob (3rd club is drawn on the 8th selection)
= P(7 non 3 clubs, and one 3 club)
= 
b) P(first 7 cards non 3 club) = 
With replacement
c) P(7 non 3 clubs and 8th 3club)
= 
d) P(atleast first 7 cards non3 club) =1-P(3 club in the 7th draws )=