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2 years ago

How do you solve and simplify

Mathematics

1 answer:

DedPeter [7]2 years ago

7 0

F(x) = 1/(x+2) & g(x) = x/(x-3)

(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)

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3 years ago

In the diagram below, AB = BD = BC, and mZA = 24°. Find<br> mZC.

snow_tiger [21]

Answer:

m∠C = 66°

Step-by-step explanation:

Since AB = BD, it means this triangle is an Isosceles triangle and as such;

∠BAD = ∠BDA = 24°

Thus, since sum of angles in a triangle is 180,then;

∠ABD = 180 - (24 + 24)

∠ABD = 180 - 48

∠ABD = 132°

We are told that BC = BD.

Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC

Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.

Thus;

132 = ∠BCD + ∠BDC

Since ∠BCD = ∠BDC, then

∠BCD = ∠BDC = 132/2

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2 years ago

What is the center of the circle that has a diameter whose endpoints are (9, 7) and (-3, -5)?

emmasim [6.3K]

Answer: OPTION B.

Step-by-step explanation:

Given the endpoints of the diameter of the circle, we need to find the midpoint, which is the center of the circle.

The following formula is used to calculate the Midpoint:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Given the endpoints of the diameter of the circle:

$(9, 7)\ and\ (-3, -5)$

We can identify that:

$x_1=9\\x_2=-3\\y_1=7\\y_2=-5$

Then, we can substitute these values into the formula:

$M=(\frac{9+(-3)}{2},\frac{7+(-5)}{2})\\\\M=(3,1)$

Therefore, the center of the circle is: $(3,1)$

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3 years ago