A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2).
rule (x + 7, y − 1)
To find new coordinates we add 7 with x and subtract 1 from y
A(−2, 2) -----> A' (5,1)
B(−2, 4) -------> B' (5, 3)
C(2, 4) ---------> C' (9, 3)
D(2, 2) -------->D' (9, 1)
Characteristics
When we connect all the points by line segments, the line A'B' will be parallel to C'D'.
Also, B'C' parallel to A'D'.
All the four lines forms a rectangle .
11111111111111111-111111111-1
The answer is X = 12.
This is how to get that answer: the formula for the intersecting secant and tangent outside the circle is a^2 = b(b+c) If you use the numbers in the pic you will get x^2 = 9(9+7) so the number after the equal sign will be 144, so x^2 = 144. To undo the square youre gonna use the square root on both sides, so you have X = 12.
Um i would need more details
But i thing you would add those together