Please help me out!!!!!!!

Prove that is here<br><img src="https://tex.z-dn.net/?f=1%20-%20cos%20%7B2%7Da%20%5Cdiv%201%20-%20sin%20a%7B2%7D%20%20%3D%20tan%

garri49 [273]

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\boxed{\sf \dfrac{cosA}{sinA}=cotA}$

$\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}$

$\\ \sf\longmapsto 1-cot2A$

$\\ \sf\longmapsto 1-\dfrac{1}{tan2A}$

$\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}$

$\\ \sf\longmapsto tan2A$

8 0

3 years ago

D-7 =-18<br> What’s the answer?

AlexFokin [52]

Answer:

D = - 9

Step-by-step explanation:

D - 7 = -18

D - 7 + 7 = -18 + 7

D = -9

5 0

3 years ago

Read 2 more answers

Which of these is closest in size to 1?<br> 0.95<br> 1.05<br> 0.960<br> 1.040<br> 0.95

yuradex [85]

1.05....................

8 0

2 years ago

How do you find the center of dilation for a negetive dilation?

Andrei [34K]

the Answer:

Notice that the "image" triangles are on the opposite side of the center of the dilation (vertices are on opposite side of O from the preimage). Also, notice that the triangles have been rotated 180º.

Step-by-step explanation:

A dilation is a transformation that produces an image that is the same shape as the original but is a different size. The description of a dilation includes the scale factor (constant of dilation) and the center of the dilation. The center of dilation is a fixed point in the plane about which all points are expanded or contracted. The center is the only invariant (not changing) point under a dilation (k ≠1), and may be located inside, outside, or on a figure.

Note:

A dilation is NOT referred to as a rigid transformation (or isometry) because the image is NOT necessarily the same size as the pre-image (and rigid transformations preserve length).

What happens when scale factor k is a negative value?

If the value of scale factor k is negative, the dilation takes place in the opposite direction from the center of dilation on the same straight line containing the center and the pre-image point. (This "opposite" placement may be referred to as being a " directed segment" since it has the property of being located in a specific "direction" in relation to the center of dilation.)

Let's see how a negative dilation affects a triangle:

Notice that the "image" triangles are on the opposite side of the center of the dilation (vertices are on opposite side of O from the preimage). Also, notice that the triangles have been rotated 180º.