I’m a little confused by the question and the problem, is there a picture of the problem you could add?
Answer:
5 and negative 5
Step-by-step explanation:
The absolute value is the distance from 0 five and negative 5 are both the same distance from zero
Answer:
Step-by-step explanation:
<u>Step 1: Find the a, b, and c values</u>
The a value is: 3
The b value is: -4
The c value is: -20
Answer:
Answer:
There is no sufficient evidence to reject the company's claim at the significance level of 0.05
Step-by-step explanation:
Let 
be the true mean weight per apple the company ship. We want to test the next hypothesis
vs 
(two-tailed test).
Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by
which is normally distributed. The observed value is
. The rejection region for 
is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.
41/19 as a decimal is 2.157895
the nearest hundredth: 2.16
