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scoundrel [369]
2 years ago
9

Find the value of x. please explain how you got it :)

Mathematics
1 answer:
sertanlavr [38]2 years ago
4 0

Answer:

x=65°

Step-by-step explanation:

Next to x would be 70. (180-110=70).

Since this is an equilateral triangle, the other angle is also 70.

180-70-70=40, so the third angle is 40.

Since this is a right angle, the other angle is 50 (90-40=50).

Since that is 50, and this is an equilateral triangle, the other two angles have to be the same.

180-50=130

130÷2=65

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The maximum weight allowed per car on The Twister carnival ride is 263 pounds. Your friend weighs 86 pounds. To be able to ride
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Answer is 177
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8 0
3 years ago
8y + 7y <br> in standard form
dybincka [34]

Answer:

15y

Step-by-step explanation:

8y + 7y

first, we add the numbers which is 8+7 = 15

now we add the ys that = y+y= y ( when you add any alphabet letter the answer will be itself .)

then we add 15 + y but we can not add these but we can write it as 15y

= 15y

have a wonderful day

4 0
3 years ago
Quinn is determining the area of a trapezoid. His work is shown below.
SOVA2 [1]

Answer:

A = a + b / 2 x h

Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
2 years ago
A system of equations that has at least one solution is called inconsistent.
solmaris [256]

False. Because if it has one then it is consistent.

Source: If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line. If a system has no solution, it is said to be inconsistent. (https://www.varsitytutors.com/hotmath/hotmath.../consistent-and-dependent-systems)

8 0
3 years ago
Read 2 more answers
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