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Nadya [2.5K]
4 years ago
13

Patricia stands on a hill at an angle of 30 degrees. there is enough friction to stop her from sliding down the hill. Which free

-body diagram shows the forces acting on her?

Physics
1 answer:
makvit [3.9K]4 years ago
4 0

Correct free-body diagram is option A)

Explanation:

There are three forces acting on Patricia:

  • Her weight, which is the force of gravitational attraction exerted by the Earth on her, whose magnitude is mg (where m= mass and g= acceleration of gravity). The direction of this force is vertically downward.
  • The normal force, exerted by the plane on Patricia, which acts always up perpendicular to the plane
  • The force of friction, which prevents Patricia from sliding. The force of static friction acts in the direction opposite to the direction of motion if the body is let moving: so here, the force of friction acts up along the plane (parallel to the plane)

Therefore, the correct choice here is option A), because:

  • The weight acts vertically downward
  • The normal force acts perpendicular to the plane
  • The force of friction acts parallel to the plane

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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7 0
3 years ago
A body has a velocity of 143 km/hr. Find its value in m/s.
kozerog [31]
39.72 m/s is the velocity of the body.

3 0
4 years ago
3b. Grace drives her car with a constant speed
miskamm [114]

Time = (distance covered) / (speed)

Time = (224 mi) / (56 mi/hr)

<em>Time = 4 hours</em>

3 0
3 years ago
three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25
ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

5 0
3 years ago
An object travels back and forth along a straight line. its velocity, in centimeters per second, is given by the function v(t) =
algol13

The correct option for the maximum velocity of the object is the option

13 cm/s.

<h3>What are Functions?</h3>

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). In mathematics, functions exist everywhere, and they are crucial for constructing physical links in the sciences.

The reason for the selection is as follows:

The known parameters of the motion of the vehicle are:

The type motion of the vehicle = Repetitive back and forth

The path of the motion of the object = Along a straight line

The function that gives the velocity in centimeters per second (cm/s) is given as follows;

v(t) = 13. sin(π/45 . t)

Where;

t = The time in seconds (a set of the input variables of the function)

v(t) = The velocity of the object (the output variables of the function)

The maximum output value of the sine function = 1, therefore;

sin(π/45 . t) = 1

The units of the of the function is cm/s

Therefore, the maximum velocity of the object is 13 cm/s

learn more about functions go to -

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8 0
2 years ago
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