Answer:
Explanation:
A ) angular velocity ω = 2π / T
= 2 x 3.14 / 60
= .10467 rad / s
linear velocity v = ω R
= .10467 x 50
= 5.23 m / s
centripetal force = m v² / R
= mg v² / gR
= 834 x 5.23² / 9.8 x 50
= 46.55 N
B )
apparent weight
= mg - centripetal force
= 834 - 46.55
= 787.45 N
C ) apparent weight
= mg + centripetal force
= 834 + 46.55
= 880.55 N.
D )
For apparent weight to be zero
centripetal force = mg
mg = mv² / R
v² = gR
= 9.8 x 50
= 490
v = 22.13 m /s
time period of revolution
= 2π R /v
2 x 3.14 x 50 / 22.13
= 14.19 s
Rolling friction ex. Riding a bike or skateboard
Sliding friction ex. Cartilage against your bone.
Fluid friction ex. Rowing a boat through the water.
Static friction ex. Trying to push a heavy object/ furniture
Answer:
The answer to your question is a = 1.3 m/s²
Explanation:
Centripetal acceleration is the motion of a body that transverse a circular path.
Data
mass = 7 kg
radius = r = 1.3 m
angular rate = w = 1.0 rev/s
centripetal acceleration = a = ?
Formula
a = rw²
Substitution
a = (1.3)(1)²
Simplification and result
a = 1.3 m/s²
