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3 years ago

3b. Grace drives her car with a constant speed

Physics

1 answer:

miskamm [114]3 years ago

3 0

Time = (distance covered) / (speed)

Time = (224 mi) / (56 mi/hr)

<em>Time = 4 hours</em>

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As the mass of an object increases, the weight of the object will ______?

Sergio039 [100]

Answer:

also increase

Explanation:

If the mass increases so will the weight.

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3 years ago

Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante

rjkz [21]

Answer:

E = 13.2 kWh

, Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

P = W / t

The work is equal to the variation of the kinetic energy, for which

P = E / t

E = P t

look for the energy consumed in one day and multiply by the days of the month in the month

E = 110 4 30

E = 13200 W h

E = 13.2 kWh

the cost of this energy is

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3 years ago

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Sivilculture isis the art and science of managing forests for desired outcomes.

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3 years ago

A positive charge moving up enters a magnetic field pointing out of the screen. What is the direction of the magnetic force on t

erma4kov [3.2K]

According to the right-hand thumb rule, the forefinger gives the velocity of charge, the thumb gives the magnetic force and the center finger gives the direction of magnetic field.

then, as shown in the picture, the <span>direction of the magnetic force on the charge is in the right direction.</span>

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4 years ago

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Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha

GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0

3 years ago