We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.
The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that.
h = √((15 in)² - (10 in)²) = √115 in
The volume of the conical part of the figure is then
V = (1/3)Bh = (1/3)(π×(10 in)²×(√115 in) = (100π√115)/3 in³ ≈ 1122.994 in³
The volume of the hemispherical part of the figure is given by
V = (2/3)π×r³ = (2/3)π×(10 in)³ = 2000π/3 in³ ≈ 2094.395 in³
Then the total volume of the figure is
V = (volume of conical part) + (volume of hemispherical part)
V = (100π√115)/3 in³ + 2000π/3 in³
V = (100π/3)(20 + √115) in³
V ≈ 3217.39 in³
Answer:
1.f 2.a 3.j 4.e
Step-by-step explanation:
you add and subtract the needed like terms
for example you can add 3x with 4x but not with 4x² because it's a different degree
Hello!
We don't need to find the exact perimeter of the fencing, just an estimate.
We will round 12 ft 3 in to 12 ft, because it is closer to 12 ft than 13 ft.
We will also round 8 ft 11 in to 9 ft because there are 12 inches in a foot, which makes 9 ft closer.
The formula for perimeter of a rectangle is:
P = 2l × 2w
The length is about 12 feet and the width is about 9 feet.
Substitute the length and width:
P = 2(12) + 2(9)
Solve:
P = 24 + 18
P = 42
Jose will need about 42 feet of fencing.
Answer:
Step-by-step explanation:
Answer:
70 min
Step-by-step explanation:
If we take the hypothesis that by the end of the fifth day he had 5h20min drums practice then the remaining time to get to 7 hours practice time would be 1h40min.
