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Vinil7 [7]
3 years ago
12

Trying to understand this question

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

option 2 I think sorry if its incorrect

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A relation is plotted as a linear function on the coordinate plane starting at point E at
Jobisdone [24]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 0}} &,&{{ 27}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ -8}}~)
\end{array}
\\\\\\
% slope  = m
\stackrel{\stackrel{average}{rate~of~change}}{slope}= {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{-8-27}{5-0}\implies \cfrac{-35}{5}\implies -7

well, when x = 0, namely at the very beginning, y = 27, thus, that IS the initial value.
4 0
3 years ago
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Write 3.617 correct to two decimal place
Sindrei [870]
We start with 3: it stays unchanged

3.


then the first decimal place also remains unchanged:

3.6


now the second decimal place:


3.61

does it remain unchanged? No! the number AFTER is is 5 or bigger (it's 7), so we need to round it up. the answer is this:

3.62
5 0
3 years ago
Help find the distance between two points?
miv72 [106K]

Answer:

4

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = B(0, 0) and (x₂, y₂ ) = (\frac{\sqrt{6} }{2}, \frac{\sqrt{58} }{2} )

AB = \sqrt{((\frac{\sqrt{6} }{2})^2 } + \{(\frac{\sqrt{58} }{2})^2 }

= \sqrt{\frac{6}{4} } + \frac{58}{4}

= \sqrt{\frac{64}{4} }

= \sqrt{16}

= 4

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3 years ago
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bulgar [2K]
She needs one more cup of flower
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3 years ago
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What is40.99 times 2.1
inessss [21]

Answer:

40.99* 2.1= 86.079

Step-by-step explanation:

7 0
3 years ago
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