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vfiekz [6]
3 years ago
15

a student achieved the following grades on his tests :87,95 ,76 and 88 percent . he wants 85 percent or better overall . what gr

ade should he must get in his last test to achieve that average
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

Atleast 79

Step-by-step explanation:

Average 》 85

If 5 tests,

Sum 》 85×5

Sum 》 425

Let the fifth test score be X

X + 87 + 95 + 76 + 88 》 425

X 》425 - 346

X》79

m_a_m_a [10]3 years ago
4 0

Answer:

Step-by-step explanation:

87+95+76+88+x/5=85

346+x=85x5

x=425-346

x=79

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</span><span>(2x+10) + (2x+25) + (x-5) = 180
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5 0
2 years ago
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Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

8 0
3 years ago
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kobusy [5.1K]

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zimovet [89]

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Andrews [41]

Answer:

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The circumference of a circle is 82π

Therefore r can be calculated as follows

2 × π × r= 82× π

2πr= 82π

r = 82π/2π

r= 41

Hence r is 41cm

8 0
2 years ago
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