A kite is flying 10 ft. in the air. The angle of elevation is 20°. How long is the kite string?
1 answer:
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Answer:
The distance between the two parallel lines is y = -56·x - 1 and the parallel line that passes through the point (6, -4) is 5.91 units
Step-by-step explanation:
The parameters given are;
Equation of the line y = -56·x - 1
The point the parallel line passes = (6, -4)
Given that the slope and intercept form of a line is y = m·x + c
Where:
m = The slope = (y₂ - y₁)/(x₂ - x₁)
c = y- intercept
Comparing y = m·x + c with y = -56·x - 1 gives;
m = -56, c = -1
The equation of the parallel line is presented as follows
y - (-4) = (x - 6)(-56)
y = -56x +336 - 4 = -56x + 332
The formula for the distance, d, between two parallel lines is given by the following relation;
Where:
c₁ and c₂ are the coordinates of the point constant y-intercept in both equations when the line equation is written as follows;
y = -56·x - 1 → y + 56·x + 1 = 0
a and b are the x and y coefficients
Which gives;
which gives