1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Evgen [1.6K]
3 years ago
7

A(n) 10.7 g bullet is shot into a(n) 4588 g wooden block standing on a frictionless surface. The block, with the bullet in it, a

cquires a speed of 1.74 m/s. Calculate the speed of the bullet before striking the block. Answer in units of m/s
Physics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

v = 747.83 m/s

Explanation:

given,

mass of bullet, m = 10.7 g

                             = 0.0107 Kg

mass of the wooden plank, M = 4588 g = 4.588 Kg

speed of the block and the bullet together, V = 1.74 m/s

initial speed of the plank = 0 m/s

using conservation of momentum

m v + M u = ( M + m ) V

0.0107 x v + 0 = (4.588 + 0.0107) x 1.74

0.0107 v = 8

v = 747.83 m/s

now, speed of the bullet is equal to 747.83 m/s.

You might be interested in
If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________
siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

V_e=\sqrt{\dfrac{2GM}{r}}

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

V_e=\sqrt{\dfrac{2GM}{r\times 2}}

V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

To know more about escape velocity follow

brainly.com/question/14042253

#SPJ4

8 0
2 years ago
Action-reaction forces are not balanced forces because of what?
lara [203]

Oh but they are !

Newton's 3rd law of motion says that for every action, the <em><u>re</u></em>action is
equal and opposite.  That's as balanced as you can get.


4 0
4 years ago
Argon gas enters steadily an adiabatic turbine at 900 kPa and 450C with a velocity of 80 m/s and leaves at 150 kPa with a veloc
Crazy boy [7]

Answer:

Temperature at the exit = 267.3 C

Explanation:

For the steady energy flow through a control volume, the power output is given as

W_{out}= -m_{f}(h_{2}-h_{1} + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})

Inlet area of the turbine = 60cm^{2}= 0.006m^{2}

To find the mass flow rate, we can apply the ideal gas laws to estimate the specific volume, from there we can get the mass flow rate.

Assuming Argon behaves as an Ideal gas, we have the specific volume v_{1}

as

v_{1}=\frac{RT_{1}}{P_{1}}=\frac{0.2081\times723}{900}=0.1672m^{3}/kg

m_{f}=\frac{1}{v_{1}}\times A_{1}V_{1} = \frac{1}{0.1672}\times(0.006)(80)=2.871kg/sec

for Ideal gasses, the enthalpy change can be calculated using the formula

h_{2}-h_{1}=C_{p}(T_{2}-T_{1})

hence we have

W_{out}= -m_{f}((C_{p}(T_{2}-T_{1}) + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})

250= -2.871((0.5203(T_{2}-450) + \frac{150^{2}}{2\times 1000} - \frac{80^{2}}{2\times 1000})

<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>

evaluating the above equation, we have T_{2}=267.3C

Hence, the temperature at the exit = 267.3 C

5 0
3 years ago
Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod
aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force=\frac{Gm_{1}m_{2} }{r^{2}}

Coulombs's Law= \frac{Kq_{1}q_{2} }{r^{2}}

6 0
4 years ago
Read 2 more answers
What is a real life example of something impermeable? (please help now!!) (due tomorrow!!)
Nutka1998 [239]
Impermeable is a substance that is water proofed e.g glass, aluminium e.t.c <span />
6 0
4 years ago
Other questions:
  • A plastic rod that has been charged to -21 nc touches a metal sphere. afterward, the rod's charge is -8 nc. (a) what kind of cha
    13·1 answer
  • You have a beaker with a layer of olive oil floating on top of water. A ray of light travels through the oil and is incident on
    12·1 answer
  • . At a frequency ω1, the reactance of a certain capacitor equals that of a certain inductor.
    6·2 answers
  • How, if at all, would the equations written in Parts C and E change if the projectile was thrown from the cliff at an angle abov
    12·1 answer
  • What is the speed of a proton after being accelerated from rest through a 5.7×107 v potential difference? express your answer us
    15·1 answer
  • WHICH SHOULD NOT BE PART OF SCIENTIFIC INQUIRY
    13·1 answer
  • What type of wave has a wavelength?<br><br><br>​
    6·1 answer
  • 7. If a hummingbird hovers 30 cm in front of a window, what will it see?
    15·1 answer
  • A whale comes to the surface to breathe and then dives at an angle 24 degrees to the horizontal surface of the water. The whale
    13·1 answer
  • Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!