3 years ago

The diagram below shows a 1.0 x 105newton truck at rest on a hill that makes an angle of 8.0° with the

Physics

1 answer:

Digiron [165]3 years ago

7 0

Answer:

$it \: is \: mg \sin(8.0 \degree) \\ = 1.0 \times 10 {}^{5} \times \sin(8.0 \degree) \\ = 9.9 \times 10 {}^{4} newtons$

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now in order to find the percentage we have

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