Question

The diagram below shows a 1.0 x 105newton truck at rest on a hill that makes an angle of 8.0° with the

Answer 1

Answer:

$it \: is \: mg \sin(8.0 \degree) \\ = 1.0 \times 10 {}^{5} \times \sin(8.0 \degree) \\ = 9.9 \times 10 {}^{4} newtons$