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const2013 [10]
3 years ago
14

7 − x −(−5x) − 10 + 4x

Mathematics
2 answers:
Levart [38]3 years ago
5 0
The person above me is correct it’s 8x-3
patriot [66]3 years ago
3 0

Answer:

8 x − 3

Hope this helps, if it does please give brainliest

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PLS HELP ME, PLS THIS IS DUE FIRST CORRECT ANSWER GETS BRAINLIEST​
shusha [124]

Answer:

A. 49 + 16 (t - 1)

Step-by-step explanation:

Plug in t = 1 to test for the first hour:

49+16(1-1)=49+16(0)=49

Test as many values as you like, but testing t = 5:

49+16(5-1)=49+16(4)=49+64=113

You can see that plugging in just a few values confirms the answer.

8 0
2 years ago
2. Which answer of
bagirrra123 [75]

Answer: B : 12+3=15

Step-by-step explanation:

A sum is the answer of an addition problem

4 0
1 year ago
Help ASAP 1-4 please
s344n2d4d5 [400]
I think that it could possibly be 12 feet but at the same time I'm not sure
6 0
3 years ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
Person A can paint the neighbor's house 6 times as fast as Person B. The year A and B worked together it
uranmaximum [27]

Person A takes 2.3 days to paint the house working alone

Person B takes 13.8 days to paint the house working alone

<em><u>Solution:</u></em>

Let "x" be the number of days it takes person A  to paint the house

Person A can paint the neighbor's house 6 times as fast as Person B

Therefore.

Number of days it takes person B to paint the house = 6x

Their rates of painting are added to get  the rate working together

\frac{\text{1 house}}{\text{x days}} + \frac{\text{1 house}}{\text{6x days}} = \frac{\text{1 house}}{\text{2 days}}

\frac{1}{x} + \frac{1}{6x} = \frac{1}{2}\\\\\frac{1 \times 6}{6x} + \frac{1}{6x} = \frac{1}{2}\\\\\frac{7}{6x} = \frac{1}{2}\\\\\ x = \frac{7}{3}= 2.3

Thus person A takes 2.3 days to paint the house working alone

Person B = 2x = 6(2.3) = 13.8

Thus person B takes 13.8 days to paint the house working alone

3 0
3 years ago
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