Ch gc cdvnjhg if Gn havin ggcdhb gts Gn
Answer:
The evaluation of the equation 3 .912+s=5.313 yields; s = 1.401
Evaluation of one variable equation
According to the questions;
We are required to evaluate the equation; 3 .912+s=5.313
Hence, we must subtract 3.912 from both sides of the equation as follows;3 .912+s -3.912 = 5.313 - 3.912.s = 1.401
Step-by-step explanation:
mark me brainliest!!
Answer:
{t|60 <= t <= 85}
Step-by-step explanation:
The temperatures were measures at different times, but does not stop the values being real numbers (i.e. not discrete, or integer values).
So the range of the function is the set of all values between the minimum and maximum measured during the measuring interval (domain) of hours two and twenty-two.
The minimum value = 60F
The maximum value = 85F
So the interval of the range is [60,85], in interval notation.
In set-builder notation, it is
{t|60 <= t <= 85}
Answer:
<em>m</em>
perpendicular
=
−
3
/4
Answer:
The answer is 4
Step-by-step explanation:
As you can tell that GCF stands for Greatest Common Factor and the common factor of 36 and 68 is 4. Hope you get the answer you wanted!
