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ASHA 777 [7]
2 years ago
5

Another one please dis test needs to be finished by 3pm

Mathematics
2 answers:
Leto [7]2 years ago
5 0

Answer:

1

Step-by-step explanation:

9-15-3+10

trasher [3.6K]2 years ago
5 0

Answer:

Step-by-step explanation:

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If I had 200 juul pods and 400 juuls how many more pods do I have to buy in order for every juul to have a pod?
Lena [83]

Answer:

You have to buy 200 more juul pods.

Step-by-step explanation;

400-200 = The amount of juul pods needed for every juul to have a pod.

400-200 = 200

6 0
3 years ago
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Which Venn diagram has shading that represents the union of set G and set I?<br> answer plslsls
Ad libitum [116K]

Answer:

  • B or the second diagram

Step-by-step explanation:

<u>The sets as per diagrams are as follows</u>

  • 1. Intersection of G and I
  • 2. Combination of G and I
  • 3. Combination of G and I excluding H
  • 4. Combination of G and I excluding common region

7 0
2 years ago
One division of a large defense contractor manufactures telecommunication equipment for the military. This division reports that
Zielflug [23.3K]

Answer:

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

Step-by-step explanation:

To reach a conclusion, we have to observe the confidence interval.

Should management conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components?

Is the upper bound of the confidence interval lower than 12% = 0.12?

If yes, it should conclude that this percentage is lower.

Otherwise, it cannot conclude.

Confidence interval:

0.0758 to 0.1339

0.1339 is higher than 0.12.

So.

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

6 0
3 years ago
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If the length of a side of a square is x CM its perimeter is​
andreev551 [17]

Square perimeter =4x cm.

The complete length that a square's edge encompasses is referred to as its perimeter. Any enclosed geometric shape's perimeter may be computed by measuring the space around it.

By calculating the total of all the sides of a square, the perimeter may be determined. The perimeter of a square will be stated as,

The perimeter of square = s + s + s + s

⇒Perimeter of square = 4s, where "s" is the side length of the square.

This is because all edges of a square are equal and each edge measures "s" units.

<h3>Calculating the perimeter of a square:</h3>

Mathematically, the formula for calculating a square's perimeter is: Square perimeter, (P) = 4 Side

⇒P= 4x cm

It is concluded that the solution is 4x cm.

Learn more about square perimeter:

brainly.com/question/11495285?referrer=searchResults

#SPJ10

7 0
2 years ago
Help!!!!!!!!!!!!!!!!
Sladkaya [172]

Step-by-step explanation:

<h3><em>In</em><em> </em><em>Solving</em><em> </em><em>This </em><em>You </em><em>Need</em><em> </em><em>to</em><em> </em><em>Cha</em><em>n</em><em>g</em><em>e</em><em> </em><em>It</em><em> </em><em>I</em><em>nto</em><em> </em><em>I</em><em>mproper</em><em> </em><em>Fractions</em><em> </em><em>First</em><em>;</em></h3>

<em>1</em><em> </em><em>2</em><em>/</em><em>5</em><em>×</em><em>3</em><em> </em><em>1</em><em>/</em><em>2</em>

<em>•</em><em>You </em><em>then</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em>5<em> </em><em>by</em><em> </em><em>the</em><em> </em><em>1</em><em> </em><em>and</em><em> </em><em>then</em><em> </em><em>add</em><em> </em><em>it</em><em> </em><em>to</em><em> </em><em>the</em><em> </em>2 <em>which</em><em> </em><em>is</em><em> </em><em>then</em><em> </em><em>going</em><em> </em><em>to</em><em> </em><em>be</em><em>;</em>

7/5× 3 1/2

<em>•</em><em>Then</em><em> </em><em>you </em><em>multiply</em><em> </em><em>the</em><em> </em>2 <em>by </em><em>the</em><em> </em><em>3</em><em> </em><em>and </em><em>then</em><em> </em><em>add</em><em> </em><em>it</em><em> </em><em>to</em><em> </em><em>the</em><em> </em>1;

7/5×7/2

•<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>you</em><em> </em><em>proceed </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>first </em><em>numerat</em><em>or</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>second </em><em>numerator</em><em> </em><em>and</em><em> </em><em>then</em><em> </em><em>also</em><em> </em><em>multi</em><em>ply</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>denominator</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>second </em><em>denomina</em><em>tor</em><em> </em><em>which </em><em>will</em><em> </em><em>be</em><em>;</em>

<em>1</em><em>4</em><em>/</em><em>1</em><em>0</em>

<em>After </em><em>this</em><em> </em><em>you </em><em>go</em><em> </em><em>on</em><em> </em><em>to</em><em> </em><em>simpl</em><em>ify</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>going </em><em>to</em><em> </em><em>be</em><em>;</em>

<em>7</em><em>/</em><em>5</em><em>(</em><em>NB</em><em>:</em><em> </em><em>It</em><em> </em><em>was </em><em>divided </em><em>by</em><em> </em><em>two</em><em>)</em>

<em>So</em><em> </em><em>mixed</em><em> </em><em>number</em><em> </em><em>in </em><em>it</em><em>'s</em><em> </em><em>simplest </em><em>form</em><em> </em><em>is</em><em> </em><em>going </em><em>to</em><em> </em><em>be</em><em>;</em>

1 2/5

<em>In</em><em> </em><em>Decimal</em><em> </em><em>form</em><em> </em><em>would </em><em>have</em><em> </em><em>been</em><em>;</em><em> </em><em>1</em><em>.</em><em>4</em>

<em>Since </em><em>the</em><em> </em><em>quest</em><em>ion</em><em> </em><em>is</em><em> </em><em>asking </em><em>for</em><em> </em><em>mixed</em><em> </em><em>number</em><em> </em><em>in </em><em>it</em><em>'s</em><em> </em><em>simpl</em><em>est</em><em> </em><em>form</em><em> </em><em>it</em><em>'s</em><em> </em><em>going</em><em> </em><em>to</em><em> </em><em>be</em><em>;</em>

<em>1</em><em> </em><em>2</em><em>/</em><em>5</em>

8 0
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