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algol13
3 years ago
5

What's the frequency of 0.19-mm-wavelength ultrasound used in fetal imaging? the waves travel at 1.5 km/s?

Physics
1 answer:
polet [3.4K]3 years ago
8 0
The basic relationship between frequency, wavelength and speed of a wave is given by:
f= \frac{v}{\lambda}
where
f is the frequency
v is the wave speed
\lambda is the wavelength

The ultrasound wave in our problem has wavelength of
\lambda = 0.19 mm = 0.19 \cdot 10^{-3}m
and speed of
v=1.5 km/s = 1.5 \cdot 10^3 m/s
So its frequency is
f= \frac{v}{\lambda}= \frac{1.5 \cdot 10^3 m/s}{0.19 \cdot 10^{-3} m}=7.89 \cdot 10^6 Hz
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d sin\theta = m\lambda

Here,

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\text{Spacing between adjacent lines} = d = 4926nm

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sin\theta = \frac{m\lambda}{d}

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3 years ago
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<em>w</em> = <em>m</em> <em>g</em> = (0.4 kg) (9.8 m/s²) ≈ 3.9 N

pointing downward.

• The ball is in free fall, so its acceleration is <em>g</em> = 9.8 m/s² (also pointing downward).

• The ball is dropped from a height of 49 m, so its height <em>y</em> at time <em>t</em> is

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Set <em>y</em> = 0 and solve for <em>t</em> :

0 = 49 m - 1/2 <em>g t</em> ²

<em>t</em> ² = (98 m) / <em>g</em>

<em>t</em> = √((98 m) / <em>g</em>) = √(10) s ≈ 3.2 s

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<em>v</em> = - <em>g t</em>

so that at the time found previously, the ball will have attained a velocity of

<em>v</em> = - <em>g</em> (3.2 s) ≈ -31 m/s

and thus a <em>speed</em> of about 31 m/s.

4 0
3 years ago
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<u>This is what I think is harmful!
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4 years ago
How are an atom of calcium-48 and an atom of calcium-47 different?
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8 0
3 years ago
A flask containing argon gas is connected to an closed-ended mercury manometer. The closed end is under vacuum. If the mercury l
iogann1982 [59]

Answer:

230 torr

Explanation:

Given that

P = 230 mm of Hg

If argon gas and mercury is in equilibrium position then the pressure on the both side will be same .

As we know that

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So the pressure of the argon will be 230 torr .

Unit conversion

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3 years ago
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