A wire with mass 50 g is stretched so that it’s ends are tied down at points 100 cm apart. The wire vibrates in its fundamental
2 answers:
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Answer:
9.31%
Explanation:
We are given that
Mass of KBr=49.3 g
Volume of solution=473 mL
Density of solution =1.12g/mL
We have to find the mass% of KBr.
Mass =
Using the formula
Mass of solution=
Mass % of KBr=
Mass % of KBr=
Mass % of KBr=9.31%
Hence, the mass% of KBr=9.31%
Answer:
The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.
Explanation:
Given that,
Weight of metal A = 12.5%
Weight of metal B = 87.5%
Length of unit cell = 0.395 nm
Density of A = 4.27 g/cm³
Density of B= 6.35 g/cm³
Weight of A = 61.4 g/mol
Weight of B = 125.7 g/mol
We need to calculate the density of the alloy
Using formula of density
....(I)
Where, n = number of atoms per unit cells
m = Mass of the alloy
V=Volume of the unit cell
N = Avogadro number
We calculate the density of alloy
We calculate the mass of the alloy
Put the value into the equation (I)
Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.