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Gwar [14]
3 years ago
6

What is the specific heat of water?

Physics
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

A) 4.18 J/g°C

Explanation:

Shalnov [3]3 years ago
7 0
The correct answer is A.
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Help guysssssssssssssssssssssssssssss
nikdorinn [45]

Answer: D) Earthquake

<em>I hope this helps, and Happy Holidays! :)</em>

5 0
3 years ago
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A cat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the rid
ioda
<span>Radius = 4.6 m
 Time for one complete rotation t = 5.5 s.
 Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
 Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
 Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
  Force of the cat Fc = 6m, m being the mass.
 Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
 equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116 So coefficient of static friction = 0.6116</span>
4 0
3 years ago
PLEASE HELP I WILL GIVE MAX POINTS
Finger [1]

you can collect water and shine a light though it and record your finings

4 0
4 years ago
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A light, rigid rod is 55.8 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at res
VMariaS [17]

To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have

KE = PE

\frac{1}{2} mv^2 = mgh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(2(55.8*10^{-2}))}

v = 4.67m/s

Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s

4 0
3 years ago
As an object sinks in a fluid, the buoyant force ____.
kiruha [24]
Beginning when the bottom of the object first touches the water,
and as it descends and more and more of it goes under, the
buoyant force on it increases during that time.

As soon as the object is completely underwater, it doesn't matter
how deep under it is, the buoyant force on it remains the same.

3 0
3 years ago
Read 2 more answers
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