Oliguria is the medical term for a decreased output of urine.
The end result is production of four haploid cells (n chromosomes, 23 in humans) from the two<span> haploid cells (with n chromosomes, each consisting of </span>two<span> sister chromatids) produced in </span>meiosis<span> I. The four main </span>steps of Meiosis II<span> are: Prophase </span>II<span>, Metaphase </span>II<span>, Anaphase </span>II<span>, and Telophase </span>II<span>.</span>
Answer:
4 possible combinations of gametes
Explanation:
The animal is considered an heterozygotic dihybrid because it involves two genes that have different alleles for both genes. The dihybrid animal undergoes meiosis to produce gametes. According to Mendel in his laws of segregation and independent assortment, the alleles of the two genes separate into gametes independently of one another to produce 4 types of gametes.
Number of possible combinations of gametes formed by an heterozygote can be determined by using 2^n, where n is the number of characters. Number of characters or genes involved in this case is 2, Hence, 2^2 = 4 gametes.
The allelic combination in the four gametes are: AB, Ab, aB, ab.
Phloem is the food conducting tissue that has a two-way flow.
Explanation:
Plants prepare food on their own and plants also have conductive cells that carry out transportation process. Plants are divided into two types based on their conductive system i.) vascular plants ii.) non vascular plants.
Vascular plants are those plants which have special conductive cells called phloem and xylem.
Xylem transports water from roots of the plants to other parts of plants and also provides mechanical support to plant. It is uni-directional.
Phloem is the food conducting tissue that transports food to plant and also have bi-directional movement.
