I think she 31 years old if im not wrong
Answer:
Exact circumference is ![7\frac{49}{150}km](https://tex.z-dn.net/?f=7%5Cfrac%7B49%7D%7B150%7Dkm)
Approximate circumference is ![7.33 km](https://tex.z-dn.net/?f=7.33%20km)
Step-by-step explanation:
We are given;
- The diameter of a circle as
![2\frac{1}{3} km](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B3%7D%20km)
We are required to determine the exact and approximate circumference of the circle.
- We know that the circumference of the circle is given by;
- Circumference = πD, where D is the diameter
Taking π as 3.14
![Circumference=3.14 (2\frac{1}{3}km)](https://tex.z-dn.net/?f=Circumference%3D3.14%20%282%5Cfrac%7B1%7D%7B3%7Dkm%29)
![=7\frac{49}{150}km](https://tex.z-dn.net/?f=%3D7%5Cfrac%7B49%7D%7B150%7Dkm)
The exact circumference of the circle is ![7\frac{49}{150}km](https://tex.z-dn.net/?f=7%5Cfrac%7B49%7D%7B150%7Dkm)
![7\frac{49}{150}km=7.327 km\\ = 7.33 km (nearest hundredth)](https://tex.z-dn.net/?f=7%5Cfrac%7B49%7D%7B150%7Dkm%3D7.327%20km%5C%5C%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%207.33%20km%20%28nearest%20hundredth%29)
Thus, the approximate circumference of the circle is ![7.33 km](https://tex.z-dn.net/?f=7.33%20km)
Answer:
Option c is correct
226 feet is the maximum height of the projectile.
Step-by-step explanation:
A quadratic equation
, ....[1]
then the axis of symmetry is given by:
![x = -\frac{b}{2a}](https://tex.z-dn.net/?f=x%20%3D%20-%5Cfrac%7Bb%7D%7B2a%7D)
As per the statement:
The path of the projectile is modeled using the equation :
....[2]
where, h(t) is the height after t time.
On comparing with [1] we have;
a = -16 and b = 48
then;
sec
Substitute this in [2] we have;
⇒
Simplify:
![h(1.5) = 226 ft](https://tex.z-dn.net/?f=h%281.5%29%20%3D%20226%20ft)
Therefore, the maximum height of the projectile at 1.5 sec is, 226 feet.
Answer:
the graph that goes through the points
(0,3), (-4,0)
Step-by-step explanation:
make y the subject
3x-4y=-12
4y=3x+12
y=(3x+12)/4
now when x=0
y=12/4=3
so coordinates (0,3)
now when y=0
0=(3x+12)/4
by multplying both sides by 4
0=3x+12
0=3 (x+4)
divide both sides by 3
0=x+4
x=-4
so coordinates (-4,0)
The distance between the helicopter and the first home is 369. 87 m
<h3>How to solve the distance using the angle of depression?</h3>
The distance between the helicopter and the first home can be found using sine law,
Therefore,
180 - 72 - 49 = 59 degrees.
Hence,
420 / sin 59 = A / sin 49°
where
A = distance form the first home to the helicopter.
cross multiply
420 sin 49 = A sin 59°
A = 420 sin 49 / sin 59
A = 316.978023694 / 0.8571673007
A = 369.869339199
A = 369. 87 m
learn more on angle of depression here:brainly.com/question/1976859
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