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3 years ago

(d)find the hcf of 21 and 84

Mathematics

2 answers:

Oxana [17]3 years ago

7 0

I m not sure about my ans.

nata0808 [166]3 years ago

6 0

Step-by-step explanation:

$21 = 3 \times 7 \\ \\ 84 = 2 \times 2 \times 3 \times 7 \\ \\ common \: factors \: = 3 \: and \: 7 \\ \\ \therefore \: hcf \: of \: 21 \: and \: 84 = 3 \times 7 = 21$

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3 years ago

\int (x+1)\sqrt(2x-1)dx

Nezavi [6.7K]

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$\int (x+ 1) \sqrt{2x-1} dx = \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15}(2x-1)^{\frac{5}{2}} + C$

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$= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \int (2x - 1)^{\frac{3}{2}}} dx\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{3}{2} + 1}}{\frac{3}{2} + 1}) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{3} \times ( \frac{(2x-1)^{\frac{5}{2}}}{\frac{5}{2} }) \times \frac{1}{2}\\\\= \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15} \times (2x-1)^{\frac{5}{2}} + C\\\\$

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3 years ago

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RideAnS [48]

The answer is 60° because it is the same as what is across

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3 years ago

(d)find the hcf of 21 and 84​

(d)find the hcf of 21 and 84