The area of a square is just side times side. So 3 * 3 = 9.
There are 4 half-circles which is the same as 2 full circles. Area of a circle is pi * the radius squared or
.
So we do 2(pi * (1.5)²) >> 2(2.25pi) = 4.5pi.
Now we add our two areas together. So the area of the whole thing is represented by the equation 4.5pi + 9. Plug this into a calculator to get your accurate measurement.
4.5pi + 9 ≈
23.137 m²
Answer:
The correct answer is C
Step-by-step explanation:
Tbh I just guessed but I got a 100% on the test, so I hoped that helped
Answer:
The solution is -22
Step-by-step explanation:
<em>The solution of an equation is the value of the variable of the equation</em>
∵ -(4x - 3) = -7(9 + x)
→ Simplify each side
∵ -(4x) - -(3) = -7(9) + -7(x)
∴ (-4x) - (-3) = -63 + (-7x)
→ Remember (-)(-) = (+) and (-)(+) = (-)
∴ -4x + 3 = -63 - 7x
→ Add 7x to both sides
∴ -4x + 7x + 3 = -63 - 7x + 7x
∴ 3x + 3 = -63
→ Subtract 3 from both sides
∵ 3x + 3 - 3 = -63 - 3
∴ 3x = -66
→ Divide both sides by 3
∴ x = -22
∴ The solution is -22
Answer:
Option B is correct
Step-by-step explanation:
Given:
f(x) = -20x^2 +14x +12 and
g(x) = 5x - 6
We need to find f/g and state its domain.
f/g = -20x^2 +14x +12/5x - 6
Taking -2 common from numerator:
f/g = -2(10x^2 - 7x - 6) / 5x -6
Factorize 10x^2 - 7x - 6= 10x^2 - 12x +5x -6
Putting in the above equation
f/g = -2(10x^2 - 12x +5x -6)/ 5x -6
f/g = -2(2x(5x-6) + 1 (5x-6)) / 5x-6
f/g = -2 ( (2x+1)(5x-6))/5x-6
cancelling 5x-6 from numerator and denominator
f/g = -2(2x+1)
f/g = -4x -2
The domain of the function is set of all values for which the function is defined and real.
So, our function g(x) = 5x -6 and domain will be all real numbers except x = 6/5 as denominator will be zero if x=5/6 and the function will be undefined.
So, Option B is correct.
First, you need convert the decimals into fraction
0.26 = 26/100 = 13/50
The next step would be drawing 50 small boxes on a piece of paper. Make it colorless.
The final stap would be giving 13 out of those 50 boxes with different color (such as black), and you're done
