5+(x-5)=x
Simplify the left side by combining like terms:
5 + x - 5 = x
5-5 = 0
x = x
X = All real numbers.
The answers is 96
Dont u just add?
Answer:
1/60 probabiliity
Step-by-step explanation:
You have two independent events that you want to put together.
Let Pr. mean "probability"
Pr(5 from 10 cards and 2 on a dice ) = Pr(5 from 10 cards) * Pr( 2 on a dice)
Pr(5 from 10 cards and 2 on a dice ) =(1/10) * (1/6)
= 1/60
Pr(5 from 10 cards and 2 on a dice ) =0.0167
or 1.67% probability
Step-by-step explanation:
since packages are similarsimilar packages. The ratio of the volumes is 8:125. Determine the dimensions of the bigger package. The dimensions of the smaller package are... Height= 45cm, Length= 80cm, and Width= 25cm.
Length of bigger package = <em><u>8</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>c</u></em><em><u>m</u></em>
Width of bigger package =<em><u>2</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>3</u></em><em><u>9</u></em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>2</u></em><em><u>5</u></em><em><u>c</u></em><em><u>m</u></em>
Height of bigger package =<em><u>4</u></em><em><u>5</u></em><em><u>×</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>/</u></em><em><u>8</u></em><em><u>=</u></em><em><u>7</u></em><em><u>0</u></em><em><u>3</u></em><em><u>.</u></em><em><u>1</u></em><em><u>2</u></em><em><u>5</u></em><em><u>cm</u></em>
Answer:

Step-by-step explanation:
Because we have to rewrite this equation in the format
, we have to divide, or factor to find basic terms,
Expanding the value of k(x), we have
. We see that each term can be divisible by 4, so we can factor out 4 to get

Now, we have two different terms getting multiplied. We can separate the two to get 
Because we are multiplying 4 by the other term, this is represented by 
Now, we can just set f(x) and g(x) to these functions:

Now, just to make sure, we can plug a value into k(x) and the same value into f(g(x)). Plugging in 1, we have (2(1)+4)2 as 2(2+4), which is 2(6) = 12.
Plugging 1 into f(g(x)), we can evaluate g(1) first, to get 1 + 2 = 3. Now, f(3) = 4(3)= 12, which is the same for k(x).