Solve for x Assume that lines which appear tangent

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%282x%2B1%29%28x-5%29%7D%7B%28x-5%29%28x%2B4%29%5E%7B2%7D%20%7D" id

dybincka [34]

i) The given function is

$f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}$

The domain is

$(x-5)(x+4)^2\ne 0$

$(x-5)\ne0,(x+4)^2\ne 0$

$x\ne5,x\ne -4$

ii) For vertical asymptotes, we simplify the function to get;

$f(x)=\frac{(2x+1)}{(x+4)^2}$

The vertical asymptote occurs at

$(x+4)^2=0$

$x=-4$

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

$2x+1=0$

$2x=-1$

$x=-\frac{1}{2}$

iv) To find the y-intercept, we substitute $x=0$ into the reduced fraction.

$f(0)=\frac{(2(0)+1)}{(0+4)^2}$

$f(0)=\frac{(1)}{(4)^2}$

$f(0)=\frac{1}{16}$

v) The horizontal asymptote is given by;

$lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0$

The horizontal asymptote is $y=0$ .

vi) The function has a hole at $x-5=0$ .

Thus at $x=5$ .

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

6 0

3 years ago

Determine whether the given value is a statistic or a parameter. A homeowner measured the voltage supplied to his home on one da

Natasha_Volkova [10]

Answer:

C. The given value is a statistic statistic for the year year because the data collected represent a sample sample.

Correct. The value reported is an statistic since represent a SAMPLE of the population of interest.

Step-by-step explanation:

The sample mean obtained was :

$\bar X =\frac{\sum_{i=1}^n X_i}{n}= 144.3$

A. The given value is a parameter parameter for the year year because the data collected represent a population population.

False. The data colected represent a sample of the population of interest, so for this case is not a parameter because we don't have the information about all the population of interest.

B. The given value is a parameter parameter for the year year because the data collected represent a sample sample.

False. First the sample average is not a parameter, and second the population mean is not equal to the sample mean most of the times.

C. The given value is a statistic statistic for the year year because the data collected represent a sample sample.

Correct. The value reported is an statistic since represent a SAMPLE of the population of interest.

D. The given value is a statistic statistic for the year year because the data collected represent a population.

False. If is an statistic can't represent the population, since the parameter represent the population not the statistic.

4 0

3 years ago

A two digit number is five times its units digit . If the digits are versed , the resulting numbered is 27 more than the origina

True [87]

52 should be the awnser

4 0

3 years ago

4. What is the unit rate for a pound of seed? Circle the correct answer choice.

Vladimir79 [104]

<h3>Answer: B) $1.75</h3>

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Explanation:

To get the unit cost, we divide the total cost over the number of pounds.

We can do this for any row

row one: ($17.50)/(10) = $1.75
row two: ($35.00)/(20) = $1.75
row three: ($52.50)/(30) = $1.75
row four: ($70.00)/(40) = $1.75

You don't need to show all four row calculations. You can simply pick one row.

This tells us that each pound costs $1.75

Put another way: the price is $1.75 per pound

3 0

2 years ago

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

gayaneshka [121]

Answer:

E is not a subspace of $\mathbb{R}^2$

Step-by-step explanation:

E is not a subspace of $\mathbb{R}^2$

In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0

3 years ago