Using the formula given: d = <span>√(3h/2)
We simply substitute the given values of h into the equation and compare the results.
For Wyatt where h = 120:
d = </span>√(3(120)/2)<span>
d = 13.42 miles
</span><span>For Shawn where h = 270:
d = </span>√(3(270)/2)<span>
d = 20.12 miles
</span>
Since the question asks for how much farther can Shawn see, we subtract the results:
20.12 - 13.42 = 6.7
Therefore, Shawn can see 6.7 miles farther.
Plug in the dimensions to the formula given using a handy dandy calculator for both problems.
1. The diameter of the bottom of the cone is 4 so the radius (half that) is 2. Volume = 1/3 * pi * (2)² * 6
= 1/3 * pi * 4 * 6
= 1/3 * pi * 24
= 8 * pi
≈ 25.1327 cm³
2. They give you all you need, the radius.
Volume = 4/3 * pi * (6)³
= 4/3 * pi * 216
= 288 * pi
≈ 904.7787 in³
Y = -2/3x + 5....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the slope and change the sign. So our perpendicular line will have a slope of 3/2 (see how I flipped -2/3 making it -3/2....and then changed the sign, making it 3/2)
y = mx + b
slope(m) = 3/2
(8,1)....x = 8 and y = 1
now we sub and find b, the y int
1 = 3/2(8) + b
1 = 12 + b
1 - 12 = b
-11 = b
so ur perpendicular equation is : y = 3/2x - 11 <==
hi,
you must replace x by the number between parenthese.
I show you with the first one and let you do the second one
p(x) = 11x^5 -11x^4 - 5x^2 +15x-8
p(-4) = 11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8
p(-4) = 11 ( -1024- 256) - 5*16 -60-8
p(-4) = 11 ( -1280) -80-60-8
p(-4) = - 14080 - 148
p(-4) = - 14 228
