Answer:
b) Chemistry
Step-by-step explanation:
To compare both scored we need to standardize the scores using the following equation:
![\frac{x-m}{s}](https://tex.z-dn.net/?f=%5Cfrac%7Bx-m%7D%7Bs%7D)
Where x is the score, m is the mean and s is the standard deviation. So, 82 on chemistry is equivalent to:
![\frac{82-75}{15}=0.4667](https://tex.z-dn.net/?f=%5Cfrac%7B82-75%7D%7B15%7D%3D0.4667)
Because the mean of the scores on the chemistry final exam is equal to 75 and the standard deviation is 15
At the same way, 80 on Calculus is equivalent to:
![\frac{80-83}{13} =-0.2308](https://tex.z-dn.net/?f=%5Cfrac%7B80-83%7D%7B13%7D%20%3D-0.2308)
Because the mean of the scores on the calculus final exam is equal to 83 and the standard deviation is 13
Now, we can compare the values. So, taking into account that -0.2308 is lower than 0.4667, we can said that the student do better in Chemistry.
Y = 200x.....the airplane travels 8000 miles in 40 hrs
Answer:
The markup percentage is 61.2
Step-by-step explanation:
Given as :
The cost price of each ornaments = $23
The sell price of each ornament = $37.08
Let The markup percentage = x
<u>Now, According to question</u>
Markup percentage =
× 100
Or, x% = ![\dfrac{37.08 - 23}{23}](https://tex.z-dn.net/?f=%5Cdfrac%7B37.08%20-%2023%7D%7B23%7D)
Or, x% = ![\dfrac{14.08}{23}](https://tex.z-dn.net/?f=%5Cdfrac%7B14.08%7D%7B23%7D)
Or, x% = 0.612
∴ x = 0.612 × 100
I.e x = 61.2
So, The The markup percentage = x = 61.2
Hence, The markup percentage is 61.2 Answer
Answer:
Step-by-step explanation:
We are told that the perimeter is 48 = 2L + 2W. This reduces to
24 = L + W. Next, substitute, one by one, the 3 widths 10 cm, 3.6 cm and w cm:
a) If W = 10 cm, 24 = L + W becomes 24 = L + 10, or L = 14 cm
b) If W = 3.6 cm, 24 = L + W becomes 24 = L + 3.6, or L = 20.6 cm
c) If W = w, 24 L + W becomes 24 = L + w, so that L = (24 - w) cm
9514 1404 393
Answer:
d. x-axis
Step-by-step explanation:
Consider a point on curve P and its (nearest) image on curve P'. The midpoint between those points is on the line of reflection. That line is the x-axis.
_____
<em>Additional comment</em>
The curve is symmetrical about the y-axis, so each point on P also has an image point that is its reflection across the origin. The reflection of P could be across both the x- and y-axes, or (equivalently) across the origin. We don't know the meaning of "xy-axis", so we suspect that is a red herring. The best choice here is "x-axis."