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2 years ago

13

X+y ≥20

1 answer:

prisoha [69]2 years ago

4 0

option is incorrect the last option should be reverse

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Mr.Q's class is having a giveaway where his students can receive 100 classroom credits. He will pull names out of a hat and sele

Sladkaya [172]

Answer:

1/1560

Step-by-step explanation:

The chance of you winning is 1/40, since there are 40 students and you are one of those students. Since, you cannot win again once you win once, you are eliminated. This leaves us with 39 people left. The chances of your friend being chosen out of the 39 people left is 1/39. Now you must multiply 1/40 and 1/39. After multiplying, you get 1/1560.

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3 years ago

What is the slope of (1,-5) and (3,-17)

Nikitich [7]

m(slope)= change in y/change in x

m=-17-(-5)/3-1

m=17+5/2

m=22/2

m=11

5 0

3 years ago

Why is it important to describe the variable in an expression?

Korvikt [17]

Answer: They show numerical value. You have to make them clear.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em /> $cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0

3 years ago

I need help I don’t remember these

Levart [38]

4. Using the given formula, replace t with 8 seconds and multiply:

343 x 8 = 2,744 meters.

5. Domain is the X value, replace x with 1/4 and solve:

1/4^2 + 2 = 2 1/8

y= 2 1/8

6 0

3 years ago