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Olin [163]
4 years ago
14

HELP PLS I NEED THIS <33

Mathematics
1 answer:
olganol [36]4 years ago
5 0

Answer:

(x - 2)^2 + (y - 2)^2 = 3

Step-by-step explanation:

The centre point of the circle is the value for x and y

And the radius is the distance from the centre to the circumference.

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How do you solve this equation, 5s^2-14s-3=0
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It's a quadratic equation. Solve it through factorisation.

5s^2 - 14s - 3 = 0
(5s + 1)(s - 3) = 0

5s + 1 = 0
or
s - 3 = 0

Therefore

s = -1/5
or
s = 3
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3 years ago
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Crazy boy [7]
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\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array}\\\\&#10;-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\&#10;%The volume of two spheres are 327\pi in^{3} and 8829\pi in^{3}&#10;\cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{8829}}\qquad &#10;\begin{cases}&#10;8829=3\cdot 3\cdot 3\cdot 327\\&#10;\qquad 3^3\cdot 327&#10;\end{cases}

\bf \cfrac{s}{s}=\cfrac{\sqrt[3]{327}}{\sqrt[3]{3^3\cdot 327}}\implies \cfrac{s}{s}=\cfrac{\underline{\sqrt[3]{327}}}{3\underline{\sqrt[3]{327}}}\implies \cfrac{s}{s}=\cfrac{1}{3}
6 0
3 years ago
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