Answer:
523.6
Step-by-step explanation:
Following the calculation, and 3.14 for pi, the answer would be 523.6
Isn’t there supposed to be a picture?
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
There are no values of x that make the equation true. No solution.
Answer:
D. 9 cm
Step-by-step explanation:
The radius of the sphere can be found by solving the volume equation for the radius.
V = 4/3πr³
3V/(4π) = r³
r = ∛(3V/(4π)) = ∛(3×3052/(4×π)) ≈ ∛728.611
r ≈ 9.0 cm
The radius of the sphere is about 9 cm.
