The answer should be different. Acids must be in water to ionize.
Mendeleev's investigations suggested previous versions did not work for all known elements : <span>best explains why Mendeleev's periodic table became the first widely accepted organized scheme for the elements.</span>
Answer:
(a). strontium iodide.
(b). SrI2.
Explanation:
This question wants to test our knowledge on qualitative part of chemistry practical.
The first part is flame test which is a physical test. The flame test that was done on the com gave red flame.
Deduction: This confirms the presence of Strontium and Calcium.
The next thing is the chemical tests.
(1). Unknown + ammonium carbonate: gives white precipitate (ppt.).
Deduction: presence of Calcium and Strontium ions
(2). Unknown + Ammonium phosphate - white ppt.
Deduction: presence of Calcium and Strontium ions.
(3). Unknown sample + ammonium sulfate - white ppt.
Deduction: presence of Strontium ion confirmed.
(3). Halide test: purple hexane layer.
Deduction: shows the presence of Iodine.
Therefore, the final conclusion can be made as;
(a). The name of the chemical compound is strontium iodide.
(b). The chemical formula for the compound is SrI2.
You could boil the liquid. If it is pure liquid than 100% of the liquid will boil off, however, if there is salt in the solution it will remain in the bottom of your beaker when the liquid has been boiled off.
[OH-] = √(Cs×Kw)/Ka
[OH-] = √(0,135×10^-14)/1,8×10^-5
[OH-] = √0,075×10^-9 = √75×10^-12 = 8,66×10^-6
pOH = -log[OH-]
pOH = -log[8,66×10^-6]
pOH ≈ 5,0625
pH + pOH = 14
pH = 14-5,0625
pH = 8,9375
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