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4 years ago

Draw the main lewis structure of nof. draw nonbonding electrons using the dot notation and bonding electrons as a bond.

Chemistry

2 answers:

navik [9.2K]4 years ago

6 0

solution is attached below

harina [27]4 years ago

5 0

Answer : The Lewis-dot structure are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The valence electrons are shown by 'dot'.

The given molecule is, $NOF$

In this molecule, the nitrogen atom is a less electronegative element as compared to oxygen and fluorine. So, the nitrogen is the central atom and oxygen and nitrogen are the neighboring atoms.

As we know that the nitrogen has '5' valence electrons, oxygen has '6' and fluorine has '7' valence electrons.

Therefore, the total number of valence electrons in $NOF$ = 5 + 6 + 7 = 18

According to Lewis-dot structure, there are 6 number of bonding electrons and 12 number of non-bonding electrons.

The Lewis-dot structure are shown below.

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Strong versus weak acids what makes a strong acid strong pogil answer key

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An acid is deemed strong if it can readily or easy "donate" a proton (H+) to the other ions in the solutions. Also, to donate or lose the proton or H+, the acid must dissociate (split into ions) in the solution. The more it can readily dissociate, the stronger the acid is.

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3 years ago

Read 2 more answers

Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo

siniylev [52]

Answer:

∆H > 0

∆Srxn <0

∆G >0

∆Suniverse <0

Explanation:

We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

Similarly, absorption of energy leads to a decrease in entropy of the reaction system. Hence the change in entropy of the reaction ∆Sreaction is negative at all temperatures.

The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

Since entropy of the surrounding= - ∆H/T, given that ∆H is positive, ∆S surrounding will be negative at all temperatures. This is so because an endothermic reaction causes the surrounding to cool down.

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3 years ago

Classify the four reactions that your group analyzed today as being either endothermic or exothermic

ArbitrLikvidat [17]

Chemical reactions are basically divided into two major classes depending on whether the reaction lose energy or gain energy from the environment during the course of the reaction. The two classes of reaction are exothermic and endothermic reaction.
An exothermic reaction is a type of reaction in which the reaction system lose energy to the environment and thus, the energy content of the reactants is more than that of the product formed. Because of this, the enthapyl change of an exothermic reaction is always negative.
An endothermic reaction is a type of reaction in which the reaction system absorb energy from the environment. Thus, the energy contents of the products is always higher than that of the reactants and the enthapyl change of the reaction is always positive. During the course of the reaction, the reaction container is usually cold to the touch because energy is been absorbed from the environment.

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3 years ago

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent compos

Volgvan

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

$percent composition element A=\frac{total mass of element A}{mass of compound} *100$

In this case, the percent composition of fluorine is:

$percent composition of fluorine=\frac{39.6 g}{60.3 g} *100$

percent composition of fluorine= 65.67%

The percent composition of fluorine is 65.67%

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4 years ago

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SashulF [63]

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3 years ago