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V125BC [204]
4 years ago
15

How many molecules and atoms of oxygen are present in 5.6 liters of oxygen (O2) at STP?

Chemistry
2 answers:
Brut [27]4 years ago
8 0

Answer:

2.5 you're welcome !!$!

denis-greek [22]4 years ago
7 0
Each mole is 22.4 liters in STP.
So 5.6L is 0.25 moles of O2.
Each mole has 6.022*10^23 molecules(avogadros number)
So 1.505*10^23 molecules of O2 and 3.01*10^23 atoms of oxygen(O).

Hope this helps
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Answer: It can be written as: V = nRT/P. "P" is pressure, "V" is volume, n is the number of moles of a gas, "R" is the molar gas constant and "T" is temperature. Record the molar gas constant "R". R = 8.314472 J/mole x K.

Explanation: That the answer

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What determines the temperature of an object at the molecular level?
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3 years ago
gA scientist is trying to discover information about an unknown metal in a compound. The formula for the compound is believed to
Hitman42 [59]

Solution :

It is given that :

The formula of the compound = $XBr_3$

And that 4.70 g of the sample contains $4.834 \times 10^{-2}$ mol of Br.

It means that :

1 mol of $XBr_3$ contains = 3 mol of Br

∴ 3 mol of $Br^-$ contain in 1 mol of $XBr_3$

$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

Thus the mol of $XBr_3$ = $1.576 \times 10^{-2}$ mol

The given mass is = 4.700 g

Therefore, the $\text{molar mass}$ of $XBr_3$  $=\frac{\text{mass}}{\text{mol}}$

                                                           $=\frac{4.700 \ g}{1.576 \times 10^{-2} \ mol}$

                                                          = 298.4 g/mol

So $\text{molar mass}$ of $XBr_3$ = $\text{molar mass}$ of X + 3 x $\text{molar mass}$ of Br

      298.4 g/mol = $\text{molar mass}$ of X + 3 x 79.90 g/mol

      298.4 g/mol = $\text{molar mass}$ of X + 239.7 g/mol

       $\text{molar mass}$ of X = 58.71 g/mol    (since 1 amu = 1 g/mol)      

Therefore the atomic mass of the unknown metal = 58.71 g/mol

So the unknown meta is Nickel.

3 0
3 years ago
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I am Lyosha [343]

Answer:

i think b or c

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5 0
2 years ago
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