How many molecules and atoms of oxygen are present in 5.6 liters of oxygen (O2) at STP?
2 answers:
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The molality of the solution = 17.93 m
<h3>Further explanation</h3>Given
6.00 L water with 6.00 L of ethylene glycol(ρ=1.1132 g/cm³= 1.1132 kg/L)
Required
The molality
Solution
molality = mol of solute/ 1 kg solvent
mol of solute = mol of ethylene glycol
- mass of ethylene glycol :
= volume x density
= 6 L x 1.1132 kg/L
= 6.6792 kg
= 6679.2 g
- mol of ethylene glycol (MW=62.07 g/mol)
=mass : MW
=6679.2 : 62.07
=107.608
- mass of water
6 L water = 6 kg water(ρ= 1 kg/L)
- molality
Explanation:
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Answer : The correct option is (c)
Explanation :
The given balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
As, 3 moles of react to give 2 mole of
So, 1 mole of react to give
moles of
Thus, the conversion factor needed to convert the number of moles of to the number of moles of
produced is
Hence, the correct option is (c)