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4 years ago

How many molecules and atoms of oxygen are present in 5.6 liters of oxygen (O2) at STP?

Chemistry

2 answers:

Brut [27]4 years ago

8 0

Answer:

2.5 you're welcome !!$!

denis-greek [22]4 years ago

7 0

Each mole is 22.4 liters in STP.
So 5.6L is 0.25 moles of O2.
Each mole has 6.022*10^23 molecules(avogadros number)
So 1.505*10^23 molecules of O2 and 3.01*10^23 atoms of oxygen(O).

Hope this helps

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goblinko [34]

Answer : The amount of heat released is, -121.04 KJ

Solution : Given,

Enthalpy of reaction, $\Delta H_{rxn}$ = -890 KJ

Mass of methane = 6 g

Molar mass of methane = 44 g/mole

First we have to calculate the moles of methane.

$\text{Moles of methane}=\frac{\text{Mass of methane}}{\text{Molar mass of methane}}=\frac{6g}{44g/mole}=0.136moles$

The given balanced reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

From the balanced reaction we conclude that

1 mole of methane releases heat = -890 KJ

0.136 moles of methane releases heat = $\frac{0.136moles}{1mole}\times -890KJ=-121.04KJ$

Therefore, the amount of heat released is, -121.04 KJ

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A solution has a volume of 375 ml and contains 12.6 moles of NaCI what is it molarity

miskamm [114]

Answer:

M = 33.6M .

Explanation:

Hello there!

In this case, according to the definition of molarity which is computed by dividing the moles of solute by the liters of solution, it is possible to realize that the moles of the solute are 12.6 mol and the liters of solution are 375/1000= 0.375 L and therefore the molarity of the solution can be calculated as follows:

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