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2 years ago

DUE TOMORROW ! PLS HELP !

Mathematics

2 answers:

V125BC [204]2 years ago

8 0

B Hope i helped buddy

cluponka [151]2 years ago

8 0

your answer is C, g + 0.33!

my reasoning is that the additional 0.33 is the percentage increase. you're still gonna need the original price, g. therefore the answer is C. good luck, and make sure to rate brainliest if this answer helped <3

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A student is given a rock that is known to have a mass of 436.8 grams. She measures the mass of the rock three different times w

love history [14]

I’m not sure just need to answer questions to help me so sorry

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3 years ago

Cora paid 16/100 of a dollar to buy a postcard from Grand Canyon National park in Arizona. What is 65/100 written as a

Lana71 [14]

Answer:

$.65 (sixty five cents)

Step-by-step explanation:

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2 years ago

3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1

muminat

Answer:

the equation is : x²-x-12

Step-by-step explanation:

the quadratic equation is in the form of : y=ax²+bx+c

the product of the zeros is -12 and the sum is 1

b = - 1

c=-12 (product)

y=x²-x-12

check : factorize first (x+3)(x-4)=0

either x+3=0 then x=-3

or x-4=0 then x=4

-3*4=-12

-3+4=1

the equation is : x²-x-12

3 0

3 years ago

Round 0.42 to the nearst tenth

Archy [21]

0.4 because if it’s five or more, add one more. If it’s four or less, let it rest.

4 0

3 years ago

Find the missing dimension of the prism. Round your answer to the nearest hundredth.

Nitella [24]

Answer:

$x = 6.99in$

Step-by-step explanation:

Given

$l =2in$

$Volume = 72.66in^3$

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

$Base\ Area= \frac{3\sqrt 3}{2}l^2$

This gives:

$Base\ Area= \frac{3\sqrt 3}{2} * 2^2$

$Base\ Area= \frac{3\sqrt 3}{2} * 4$

$Base\ Area= 3\sqrt 3 * 2$

$Base\ Area= 6\sqrt 3$

Side x represents the height.

So, we have:

$Volume = Base\ Area*x$

Make x the subject

$x = \frac{Volume }{ Base\ Area}$

$x = \frac{72.66in^3}{6\sqrt 3 in^2}$

$x = \frac{72.66}{6\sqrt 3}in$

$x = \frac{12.11}{\sqrt 3}in$

$x = 6.99in$ --- approximated

6 0

3 years ago