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Alona [7]
3 years ago
13

The value of √2+√2+2cos4x is?

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

2.82

Step-by-step explanation:

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Jada has 7/8 cup of cheese. Her cheese bread recipe calls for 1/6 cup of cheese. How many times can she make her recipe with the
riadik2000 [5.3K]
Divide (1/6 cup cheese) into (7/8 cup cheese):

7
--
8          7     6
----- = --- * --- = 42/8 = 5 2/8 = 5 1/4 = 5.25
1          8     1
--
6

She can prepare her recipe 5 times, with some material left over.
5 0
3 years ago
What is the value of the x variable in the solution to the following system of equations?
harkovskaia [24]
Its A. x=4

procedure: 3*equation1 - 2*equation2 ⇒ x=4
8 0
3 years ago
P- 2/3=5/6 pls help now
Nady [450]

Answer:idk the answer just doing this for the B

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
In triangle ABC, AB=10, BC=8, and angle B=30. In triangle KLJ, LJ=20, JK=16, and angle L=30. State whether the triangles are sim
Margaret [11]

Answer:

They are not similar.

Step-by-step explanation:

In triangle ABC, the angle we are given is in between the two defined sides(AB and BC with angle B). If these triangles were similar, we would see this with the SAS postulate.

In triangle KLJ, the angle is not in between the two sides, so they are not similar according to any of these two postulates.

6 0
9 months ago
Find the measures of center for following. Data Frequency 30 - 34 1 35 - 39 0 40 - 44 3 45 - 49 7 50 - 54 5 55 - 59 10 60 - 64 1
dalvyx [7]

Answer: the mode is 67.2

Step-by-step explanation:

Given that;

Data               Frequency

30 - 34                 1

35 - 39                0

40 - 44                3

45 - 49                7

50 - 54                5

55 - 59               10

60 - 64               10

65 - 69              21

70 - 74               12

Mode = ?

we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69  

Lower class boundary of the modal group; L = 65

Frequency of the group before the modal group; Fm-1 = 10

Frequency of the modal group; Fm = 21

Frequency of the group after the modal group; Fm+1 = 12

Group width; G = 4

Now using the formula

Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W

so we substitute

Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4

= 65 + [ 11 / 20] × 4

= 65 + 2.2

= 67.2    

Therefore the mode is 67.2

3 0
2 years ago
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