Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
x ≤ 3
Step-by-step explanation:
Given
2(4 + 2x) ≥ 5x + 5 ← distribute parenthesis on left side
8 + 4x ≥ 5x + 5 ( subtract 4x from both sides )
8 ≥ x + 5 ( subtract 5 from both sides )
3 ≥ x , then
x ≤ 3
Answer:
0.95
(Don't have paper, because I accidentally threw away paper )
By definition we have that the average rate of change is given by:
AVR = (f (x2) - f (x1)) / (x2 - x1)
Substituting the values we have:
AVR = (204 - (-6)) / (10 - 0)
Rewriting we have:
AVR = (204 + 6) / (10 - 0)
AVR = 210/10
AVR = 21
Answer:
the average rate of change for f (x) from x = 0 to x = 10 is:
AVR = 21
Answer:
2
Step-by-step explanation:
