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monitta
3 years ago
15

PLEASE HELP! I'LL GIVE BRAINLIEST!! 50 POINTS!!!

Mathematics
1 answer:
kogti [31]3 years ago
7 0

Answer:

1 = 9-3÷1/3+1

11 = 15-1(12÷4+1)

Step-by-step explanation:

Order of operations: PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

9-3÷1/3+1

9-9+1

0+1

<u>=1</u>

15-1(12÷4+1)

15-1(3+1)

15-1(4)

15-4

<u>=11</u>

<u></u>

<u>:) ur welcome</u>

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What is the degree of the following polynomial?<br> -4x + 5x2 – 2x5 + 12
djyliett [7]

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5

Step-by-step explanation:

The highest power of x will be the degree of the polynomial.

4 0
3 years ago
Find all solutions of the equation sin^2 x=2sinx+3
Mashutka [201]
\sin^2x=2\sin x+3
\sin^2x-2\sin x-3=0
(\sin x-3)(\sin x+1)=0

which means either \sin x=3 or \sin x=-1. The equation has no solution, since \sin x is always bounded between -1 and 1. The second has one solution at x=-\dfrac\pi2, and any number of complete revolutions will also satisfy this equation, so in general the solution would be -\dfrac\pi2+2k\pi where k is any integer.

So you could choose A=-\dfrac\pi2 and B=2.
4 0
2 years ago
Distribute –2 (–2 – 5x2).
lara31 [8.8K]

Answer:

4 + 10x^2

Step-by-step explanation:

–2 (–2 – 5x^2)

Distribute

-2 *-2 -2*-5x^2

4 + 10x^2

8 0
3 years ago
Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
2 years ago
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