Step-by-step explanation:

Solving this equation using the quadratic formula, we get two real solutions :
1.1926 or -4.1926
Now we know the values of v , we can calculate x since x is ∛ v

![x = \sqrt[3]{1.1926} = 1.0605 \\ x = \sqrt[3]{ - 4.1926} = - 1.6125](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B1.1926%7D%20%20%3D%201.0605%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B%20-%204.1926%7D%20%20%3D%20%20-%201.6125)
This is a geometric sequence with common ratio (r) = 2.
an = ar^(n - 1)
a4 = a(2)^(4 - 1) = a(2)^3 = 8a
8a = 80
a = 80/8 = 10
7th term (a7) = 10(2)^(7 - 1) = 10(2^6) = 10(64) = 640
9514 1404 393
Answer:
1. (256/3)π ft³
2. 33.49 ft³
Step-by-step explanation:
1. Put 4 ft into the formula where r is, then simplify.
V = (4/3)π(4 ft)³ = (256/3)π ft³
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2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.
V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³
Answer:
-39/2 or -19 1/2
Step-by-step explanation:
That all depends what place you want it rounded to.
Rounding to the nearest tenth, it becomes 32.6 .
Rounding to the nearest whole number, it becomes, 33 .
Rounding to the nearest ten or higher order of magnitude, it becomes zero.