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3 years ago

Can anybody tell me the volume or tell me what to multiply?

Mathematics

2 answers:

DiKsa [7]3 years ago

7 0

(2*5*3)+(2*6*3)+(6*3*2) = 102

WARRIOR [948]3 years ago

4 0

Find the volume of the larger object (AxBxC) and subtract the volume of the missing piece. 6x10x3=180; 6x3x4=72; 180-72=108; 108 is the answer.

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Suppose a researcher is conducting a hypothesis test for a mean and finds a test statistic of z=2.3z=2.3 . Which of the choices

Galina-37 [17]

Answer:

Option c. The result is significant at the 0.020.02 level.

Step-by-step explanation:

We are given the following in the question:

We are conducting a one tailed hypothesis test with alternate hypothesis

$H_A: \mu > \mu_0$

The z test calculated for the same is

z=2.3

We calculate the p-value from the standard normal table.

p value = 0.010724 at 0.05 significance level.

The result is significant

p value = 0.010724 at 0.01 significance level.

The result is not significant

p value = 0.010724 at 0.02 significance level.

The result is significant at 0.02 significance level.

Thus, the correct answer is

Option c. The result is significant at the 0.020.02 level.

3 0

3 years ago

Please help i dont understand this

zavuch27 [327]

Answer:

It is the same-side interior angle of B which is the vertical angle of 100 (?)

Step-by-step explanation:

4 0

3 years ago

What is the scale factor from figure A to figure B?

SCORPION-xisa [38]

Answer:

Figure A sides are 1/4 the size of Figure B

The top of Figure A = 4, the top of Figure B = 1.

Divide 1 by 4 to get the scale factor, which is 1/4 as a fraction or 0.25 as a decimal.

Step-by-step explanation:

3 0

3 years ago

Value of ratio 3/4 to 2

MrMuchimi

Answer:

3/8 or 0.375

Step-by-step explanation:

0.75/2 = 3/8

4 0

3 years ago

Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp

Maslowich

If $p(3-2i)=0,$ then complex number $3-2i$ is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated $3+2i$ is also a root of polynomial.

Then the polynomial will be of a form

$p(x)=(x-(3-2i))(x-(3+2i))(x-a).$

Since $p(0)=-52,$ then

$-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.$

Therefore,

$p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.$

3 0

3 years ago