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Over [174]
4 years ago
9

Solve the equation: 5/6 = 1/3 + D

Mathematics
1 answer:
Sauron [17]4 years ago
8 0
Answer: \frac{1}{2} 
 
Explanation:
\frac{5}{6} =  \frac{1}{3}  + D 
\frac{5}{6}  -  \frac{1}{3} = \frac{1}{3}  -  \frac{1}{3} + D 
\frac{5}{6} -  \frac{1}{3} = D 
\frac{5}{6} - 2(\frac{1}{3}) = D
\frac{5}{6} - \frac{2}{6} = D 
\frac{3}{6} = D = \frac{1}{2}
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1 in 12 chance of landing on 3

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Step-by-step explanation:

12 equal sections means probability is 1 in 12 of landing on any one numbered section.

2 in 12 or 1 in 6 chance of landing on either of two numbered sections in one attempt.

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Step-by-step explanation:

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2 years ago
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4 0
4 years ago
Read 2 more answers
3. Solve the following application of a system of linear equations.
zhuklara [117]

Answer:

Equations:

y =  14 + 9 x --- Cindy

y = 10 x --- Ruben

Solution to equation:

Time they have the same amount: 14 minutes

Number of cards they have at that time: 140 flashcards

Step-by-step explanation:

Solving (a): Variables and what they represent

The variables to use are x and y

Where x represent the minutes and y represents the number of flashcards in x minutes

Solving (b): System of linear equation

Cindy:

Existing\ Flashcards = 14

Additional = 9 per minute

Total number of flashcards (y) in x minutes is:

y =  Existing\ Flashcards + Additional * x

y =  14 + 9 * x

y =  14 + 9 x

Ruben:

Rate = 10 per minute

Total number of flashcards (y) in x minutes is:

y = Rate * x

y = 10 * x

y = 10 x

Solution to Equations:

Time they have the same amount.

To do this, we equate both expressions

i.e.

10x = 14 + 9x

Collect Like Terms

10x - 9x = 14

x = 14

Number of cards they have at that time.

Here, we simply substitute 14 for x in any of the equations.

y = 10 x

y = 10 * 14

y = 140

or

y =  14 + 9 x

y = 14 + 9 * 14

y = 14 + 126

y = 140

4 0
3 years ago
Ken bought 2 video games and 1 DVD for a total of $105. Jerome bought 1 video game and 4 DVDs for a total of $80. Which system o
Zigmanuir [339]

Answer:

I think that the Linear system of equations can be used to find the cost.

Step-by-step explanation:

5 0
3 years ago
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