All categories

3 years ago

Solve the equation: 5/6 = 1/3 + D

1 answer:

8 0

Answer: $\frac{1}{2}$

Explanation:
$\frac{5}{6} = \frac{1}{3} + D$
$\frac{5}{6} - \frac{1}{3} = \frac{1}{3} - \frac{1}{3} + D$
$\frac{5}{6} - \frac{1}{3} = D$
$\frac{5}{6} - 2(\frac{1}{3}) = D$
$\frac{5}{6} - \frac{2}{6} = D$
$\frac{3}{6} = D$ = $\frac{1}{2}$

You might be interested in

If x=at^3 and y=bt^2 then find dy/dx

Molodets [167]

Dy/dx = (dy/dt) / (dx/dt)

dy/dt = 2bt

dx/dt = 3at^2

therefore dy/dx = 2bt/3at^2
dy/dx = 2b/3at

8 0

3 years ago

Evaluate the given expression if a = 2 and b = -4 <br> a2-b3

IceJOKER [234]

Answer:

Step-by-step explanation:

${a}^{2} - {b}^{3} \\ \\ = {(2)}^{2} - {( - 3)}^{3} \\ \\ = 4 - ( - 27) \\ \\ = 4 + 27 \\ \\ = 31$

5 0

3 years ago

What is the value of 125 ⅔ ?

horrorfan [7]

Answer:125.666

Step-by-step explanation:

8 0

2 years ago

Nine scores have an average of 8. Scores x and x+1 are added, and these increase the average to 9. Find x

Degger [83]

Answer:

x must be 13

Step-by-step explanation:

Represent the nine scores by a, b, c, d, e, f, g, h, i.

Write the following equation to indicate that the average of these nine scores is 8:

a+b+c+d+e+f+g+h+i

----------------------------- = 8, or <em>a+b+c+d+e+f+g+h+i = 72</em> if we multiply both

9 sides of this equation by 9.

Next, we add scores x and x+ 1 to

a+b+c+d+e+f+g+h+i + x + x + 1

and divide the result by 11, as there are now 11 scores instead of just 9:

a+b+c+d+e+f+g+h+i + x + x + 1

----------------------------------------------

Earlier, we saw that a+b+c+d+e+f+g+h+i = 72. We can now replace

a+b+c+d+e+f+g+h+i in the above fraction by 72:

72 + 2x + 1

------------------- = 9 (as the new average is 9)

Multiplying both sides of this equation by 11 results in:

73 + 2x = 99, or 2x = 26.

Then x must be 13, and x + 1 must be 14.

3 0

3 years ago

Solve for x in the equation X2-8x+41 = 0 -

djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation ax² + b x + c = 0

The value of x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

∴ For equation x² - 8 x + 41 = 0

Or, x = $\frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}$

Or, x = $\frac{8\pm \sqrt{-100}}{2}$

Or, x = $\frac{8\pm 10i}{2}$

∴ x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D Answer

7 0

3 years ago