<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
Answer:
- 5/7 - (3/14 + 3/14) = 2/7
See the steps of solution:
- 5/7 - (3/14 + 3/14) = Solve parenthesis first
- 5/7 - (3 + 3)/14 = Add fractions with same denominator
- 5/7 - 6/14 = Simplify
- 5/7 - 3/7 = Subtract fractions with same denominator
- (5 - 3)/7 = Simplify
- 2/7 Answer
196852205944
(Hope this helps)
Answer:
(P-2a-3b)/4=c
Step-by-step explanation:
First, isolate the variable we are solving for, c (P-2a-3b=4c). Now, divide by 4 to get c completely alone ((P-2a-3b)/4=c).