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Anon25 [30]
3 years ago
13

What is the root of 105 to 2 decimal places

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

The root of 105 to 2 decimal places Is 10.25

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Find the measure of HG¯¯¯¯¯¯¯¯.<br> A. 12<br> B. 16<br> C. 14<br> D. 7
Paraphin [41]

HG^2 = FG * (FG + EF)

Fill in the values:

(x+3)^2 = x * (7+x)

Simplify the right side:

(x+3)^2 = 7x +x^2

Rewrite the left side using the FOIL method

x^2 + 6x + 9 = 7x +x^2

Subtract x^2 from both sides:

6x +9 = 7x

Subtract 6x from both sides:

x = 9

Now you have x solve for HG

HG = x +3 = 9+3 = 12

The answer is A.

3 0
3 years ago
One number is 14 more than another. the sum of two numbers is 20. find the numbers.
patriot [66]

The number is 6 because 14+6=20 and 6 is less than 14. Hope this helps.

4 0
3 years ago
If f(p) divided by x-p and x-q have the same remainder
oee [108]
Hello,


x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)

Let's use Horner's division

.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3

The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3


Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0

And here, Mehek are there sufficients explanations?
3 0
3 years ago
-0.8b^2+7.4b+(5.6b-0.2b^2)
puteri [66]

Answer:

what? I don't understand lol

5 0
3 years ago
An average Smart TV costs $500. On Black Friday, the Smart TV goes on sale for $350. By what percent did the
Alchen [17]

Answer:

30%

Step-by-step explanation:

$500-$350=150

150/500 x 100

=30%

6 0
3 years ago
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