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Anon25 [30]
3 years ago
13

What is the root of 105 to 2 decimal places

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

The root of 105 to 2 decimal places Is 10.25

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A​ long-distance telephone company charges a rate of cents per minute or a ​-cent minimum charge per completed​ call, whichever
LiRa [457]

Answer: 50 cents

Step-by-step explanation:

Company charges 8 cents per call and the call in question is 3 minutes. Cost is;

= 3 * 8

= 24 cents

Company however stipulates that a call is 8 cents per minute or a 50​-cent minimum charge per completed​ call, whichever is greater.

<em>50 cents is greater than the per minute total charge of 24 cents so the cost will be 50 cents.</em>

8 0
3 years ago
Show that angle a+ angle b is equal to angle d​
mr_godi [17]

sum of two angles of triangle are equal to the exterior angle of triangle

8 0
2 years ago
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Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of
labwork [276]

Answer:

<em>a)  </em>G(x)= \sin x + 2<em />

<em>b) The coordinates of P are</em>

<em />\displaystyle \left( \frac{3\pi}{2},1\right)

Step-by-step explanation:

<u>Translation</u>

The dashed line shows the graph of the function

y = \sin x

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

a)

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

\boxed{G(x)= \sin x + 2}

b) The coordinates of P correspond to the value of

x = \frac{3\pi}{2}

The value of G is

\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2

Since

\sin \frac{3\pi}{2}=-1

\displaystyle G(\frac{3\pi}{2})= -1+ 2=1

The coordinates of P are

\displaystyle \left( \frac{3\pi}{2},1\right)

8 0
2 years ago
What is the 57th term of the arithmetic sequence : 11,8,5,2
andriy [413]
I think its this <span> 14 - 3*57 = 14 - 171 = -157 </span>
4 0
3 years ago
Find an asymptote of this conic section. 9x^2-36x-4y^2+24y-36=0
ki77a [65]
We will begin by grouping the x terms together and the y terms together so we can complete the square and see what we're looking at. (9x^2-36x)-(4y^2+24y)-36=0.  Now we need to move that 36 over by adding to isolate the x and y terms.  (9x^2-36x)-(4y^2+24y)=36.  Now we need to complete the square on the x terms and the y terms.  Can't do that, though, til the leading coefficients on the squared terms are 1's.  Right now they are 9 and 4.  Factor them out: 9(x^2-4x)-4(y^2-6y)=36.  Now let's complete the square on the x's. Our linear term is 4.  Half of 4 is 2, and 2 squared is 4, so add it into the parenthesis.  BUT don't forget about the 9 hanging around out front there that refuses to be forgotten.  It is a multiplier.  So we are really adding in is 9*4 which is 36.  Half the linear term on the y's is 3.  3 squared is 9, but again, what we are really adding in is -4*9 which is -36.  Putting that altogether looks like this thus far: 9(x^2-4x+4)-4(y^2-6y+9)=36+36-36.  The right side simplifies of course to just 36.  Since we have a minus sign between those x and y terms, this is a hyperbola.  The hyperbola has to be set to equal 1.  So we divide by 36.  At the same time we will form the perfect square binomials we created for this very purpose on the left: \frac{(x-2)^2}{4}- \frac{(y-3)^2}{9}=1.  Since the 9 is the bigger of the 2 values there, and it is under the y terms, our hyperbola has a horizontal transverse axis.  a^2=4 so a=2; b^2=9 so b=3.  Our asymptotes have the formula for the slope of m=+/- \frac{b}{a} which for us is a slope of negative and positive 3/2.  Using the slope and the fact that we now know the center of the hyperbola to be (2, 3), we can solve for b and rewrite the equations of the asymptotes.  3= \frac{3}{2}(2)+b give us a b of 0 so that equation is y = 3/2x.  For the negative slope, we have 3=- \frac{3}{2}(2)+b which gives us a b value of 6.  That equation then is y = -3/2x + 6.  And there you go!
8 0
3 years ago
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