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3 years ago

Select all of the following that are ordered pairs of the given function.

Mathematics

1 answer:

AleksAgata [21]3 years ago

7 0

Answer:

I don’t for sure know the answer but I think it’s ”1”

Step-by-step explanation:

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Kellens bill at a restaurant before tax and tip is $22 if tax is 5.25% and we wants to leave 15% of the bill including the tax o

Musya8 [376]

22x0.0525 = 1.155

22 x 0.15 = 3.3 (tip)

22 + tax + tip = 26.46 (unless the tax is actually 11.55)

3 0

3 years ago

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What is r in this equation?<br> 3 3/4 + r = 5 3/8

gayaneshka [121]

Answer:

r is 1 5/8

Step-by-step explanation:

3 3/4 is the same as 3 6/8, now both denominators are the same.

5 3/8 - 3 6/8 is the same as 43/8-30/8 which is 13/8, or in mixed number form, 1 5/8.

So r=1 5/8

8 0

3 years ago

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Please help me out on this question :)

d1i1m1o1n [39]

Answer:

my teacher gave me the exact answer for this

Step-by-step explanation:

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3 years ago

What is the estimate of 212,514+396,705

Evgesh-ka [11]

Change 212,514 into 215,000.

Change 396,705 into 400,000.

--------

Estimate:

215,000 + 400,000 = 615,000

Therefore:

212,514 + 396,705 ≈ 615,000

4 0

3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

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