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3 years ago

14

A closed cylindrical tank had a diameter and height 7m what is the capacity of the tank

1 answer:

bezimeni [28]3 years ago

3 0

Area of a cylinder is pi*r^2*h

The radius is half the diameter.

So the radius is 3.5

3.14*3.5^2*7=269.255 cubic meters.

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How much is a milliliter

Sphinxa [80]

-- 236 of them make 1 cup
-- 946 of them make 1 quart
-- the volume of a tiny cube that's 1 centimeter along each edge
-- 16.4 of them in a little cube that's 1 inch along
-- 4.9 of them make a standard cooking teaspoon
-- a perfume that cost $50 an ounce would cost $1.69 per milliliter

3 0

3 years ago

Read 2 more answers

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

To thase who missed the other ones 4+5-6/7*8-7

hoa [83]

Answer:

-6.67 im pretty sure

Step-by-step explanation:

4+5=9

9-6=3

3/7=0.43

0.43-7=-6.67

the calculator says sum else but like who cares right? lol

4 0

3 years ago

Read 2 more answers

Sharon purchased a used car for $24,600. The car depreciates exponentially by 8% per

Tju [1.3M]

Answer:

The value of car after 5 years of exponentially depreciation is $16,213.36

Step-by-step explanation:

The initial amount of the car = i = $24,600

The depreciates rate of interest applied = r = 8%

Let The value of car after n years = A

The number of years = n = 5 years

Now,According to question

The value of car after n years = initial price of car × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, The value of car after 5 years = i × $(1-\dfrac{\textrm r}{100})^{\textrm n}$

Or, $A = $24,600 × $(1-\dfrac{\textrm 8}{100})^{\textrm 5}$

Or, $A = $24,600 × $(0.92)^{5}$

Or, $A = $24,600 × 0.65908

Or, $A = $16,213.36

So, The value of car after 5 years = A = $16,213.36

Hence , The value of car after 5 years of exponentially depreciation is $16,213.36 . Answer

5 0

3 years ago

Help please first one to answer gets brainly

Dominik [7]

Answer:

The answer is D. The last option. C for the second question. A for the third question.

4 0

2 years ago