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Ivanshal [37]
3 years ago
8

5 times what thousandths equals 0.045?

Mathematics
1 answer:
notka56 [123]3 years ago
7 0
.009 is the answer to this equation
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Use the discriminant to determine the number and type of solutions the equation has.
lidiya [134]
Discriminant = square root (b^2 -4*a*c)
square root (64 -4*1*12) =
square root (16) =
4
Therefore it has 2 rational soltions


4 0
3 years ago
Please helppp (NO LINKS!!!)
n200080 [17]

Answer:

DE = 39.64840676

CE = 35.3269891

Step-by-step explanation:

SOH CAH TOA

Thus,

sin(27) = 18/DE

tan(27) = 18/CE

DE = 39.64840676

CE = 35.3269891

4 0
2 years ago
Write four decimals with the digit four in a different place in each ones, tenths , hundredths, and thousandths .Then write a st
crimeas [40]
4.1.....the 4 in the ones place is 10 times bigger then the 4 in the tenths place and 100 times bigger then the 4 in the hundredths place and 1000 times bigger then the 4 in the thousandths place

2.4..the 4 in the tenths place is 10 timed bigger then the 4 in the hundredths place and 100 times bigger then the 4 in the thousandths place

3.14...the 4 in the hundredths place is 10 times bigger then the 4 in the thousandths place

5.124...this 4 in the thousandths place is the smallest
8 0
3 years ago
Quick Computing Company produces
olganol [36]

Answer:

c(x) = 2x^2 + 6x + 25

Completed question;

Quick Computing Company produces calculators. They have found that the cost, c(x), of making x calculators is a quadratic function in terms of x. The company also discovered that it costs $45 to produce 2 calculators, $81 to produce 4 calculators, and $285 to produce 10 calculators. Derive the function c(x).

Step-by-step explanation:

Given that;

the cost, c(x), of making x calculators is a quadratic function in terms of x.

c(x) = ax^2 + bx + c

Substituting the 3 case scenarios given;

it costs $45 to produce 2 calculators,

45 = a(2^2) + b(2) + c

45 = 4a + 2b +c .......1

$81 to produce 4 calculators,

81 = a(4^2) + b(4) + c

81 = 16a + 4b + c .......2

and $285 to produce 10 calculators.

285 = a(10^2) + b(10) + c

285 = 100a + 10b + c .......3

Solving the simultaneous equation;

Subtracting equation 1 from 2, we have;

36 = 12a + 2b ......4

Subtracting equation 1 from 3

240 = 96a + 8b .......5

Multiply equation 4 by 4

144 = 48a + 8b ......6

Subtracting equation 6 from 5, we have;

96 = 48a

a = 96/48

a = 2

Substituting a = 2 into equation 4;

36 = 12(2) + 2b

36 = 24 + 2b

2b = 36-24 = 12

b = 12/2 = 6

b = 6

Substituting a and b into equation 1;

45 = 4(2) + 2(6) +c

45 = 8 + 12 + c

c = 45 - (8+12)

c = 25

Since a = 2 , b = 6 and c = 25, the quadratic equation for c(x) is ;

c(x) = ax^2 + bx + c

c(x) = 2x^2 + 6x + 25

5 0
3 years ago
Solve for x: 12(x-2)<24
il63 [147K]
<span>12(x-2)<24
Multiply the number outside the parenthesis with the numbers inside the parenthesis
12x-24<24
Add 24 to both sides
12x<48
Divide both sides by 12 so that x is the only thing remaining on the left side is the x variable.
Final Answer: x<4</span>
6 0
3 years ago
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