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Sholpan [36]
3 years ago
11

Suppose we want to choose 6 letters, without replacement, from 15 distinct letters. (A) how many ways can this be done, if the o

rder of choices is not taken into consideration? (B) How many ways can this be done, if the order of choices is taken into consideration?
Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

Below in bold.

Step-by-step explanation:

A.This is the number of combinations of 6 from 15

= 15C6

=  15! / (15-6)! 6!

= 5,005 ways.

B.  This is the number of permutaions of 6 from 15:

= 15! / (15-6)!

= 3,603,600 ways.

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