Suppose we want to choose 6 letters, without replacement, from 15 distinct letters. (A) how many ways can this be done, if the o
rder of choices is not taken into consideration? (B) How many ways can this be done, if the order of choices is taken into consideration?
1 answer:
Answer:
Below in bold.
Step-by-step explanation:
A.This is the number of combinations of 6 from 15
= 15C6
= 15! / (15-6)! 6!
= 5,005 ways.
B. This is the number of permutaions of 6 from 15:
= 15! / (15-6)!
= 3,603,600 ways.
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