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Sholpan [36]
3 years ago
11

Suppose we want to choose 6 letters, without replacement, from 15 distinct letters. (A) how many ways can this be done, if the o

rder of choices is not taken into consideration? (B) How many ways can this be done, if the order of choices is taken into consideration?
Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

Below in bold.

Step-by-step explanation:

A.This is the number of combinations of 6 from 15

= 15C6

=  15! / (15-6)! 6!

= 5,005 ways.

B.  This is the number of permutaions of 6 from 15:

= 15! / (15-6)!

= 3,603,600 ways.

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If UV = 6 and TV = 12, what is TU?
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Answer:

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Answer:

  • <u>After 1.7 hours</u>

Explanation:

<u>1. Calculate the average speed of train B</u>

  • 60mph = 3/4 (s) ⇒ s = 60 (4/3) mph = 80 mph

<u>2. Build a table</u>

When the two trains meet:

Train     Average speed     Distance       time (distance/average speed)

                 mph                            

A                 60                             x                        x/60

B                 80                        240 - x                (240 - x) / 80

<u>3. Write the equation</u>

The time, when the two trains meet, is the same for both trains:

                  \dfrac{x}{60}=\dfrac{240-x}{80}\\ \\ \\ 80x=14,400-60x\\ \\ 80x+60x=14,400\\ \\ 140x=14,400\\ \\ x=14,400/140\\ \\ x=102.85miles

<u>4. Calculate the time:</u>

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The two trains will meet after 1.7 hours

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