<em>x = 3</em>
<em>y = 1</em>
- <em>Step-by-step explanation:</em>
<em>Hi ! </em>
<em>6x - 5y = 13</em>
<em>9y - 15 + 2x = 0</em>
<em />
<em>6x - 5y = 13</em>
<em>2x + 9y = 15 | ×(-3)</em>
<em />
<em>6x - 5y = 13</em>
<em>- 6x - 27y = - 45</em>
<em>add</em>
<em />
<em>6x - 6x - 5y - 27y = 13 - 45</em>
<em>- 32y = - 32 | ×(-)</em>
<em>32y = 32</em>
<em>y = 1</em>
<em>replace y = 1</em>
<em>6x - 5(1) = 13</em>
<em>6x - 5 = 13</em>
<em>6x = 13 + 5</em>
<em>6x = 18</em>
<em>x = 3</em>
<em>Good luck !</em>
<em />
Answer:
x < 5
Step-by-step explanation:
<u>Step 1: Solve for x</u>
-8x + 18 > -22
-8x + 18 - 18 > -22 - 18
-8x / -8 > -40 / -8
<em><u>When dividing by negative, it flips the sign</u></em>
x < 5
Answer: x < 5
Eloise made these steps well:
Square root of negative 2x plus 1 - 3 = x
Square root of negative 2x plus 1 - 3 + 3 = x + 3
The error comes in the next step:
Square root of negative 2x plus 1 = x + 3
Square root of negative 2x plus 1 -1 = x + 3 - 1
Square root of negative 2x = x + 2
the number one is inside the root, therefore they can not be subtracted.
answer
error in the step:
Square root of negative 2x = x + 2
Answer:
15units
Step-by-step explanation:
BC is: 5x=5×3=15 units. so,Length of BC=15 units
The answer is 4
so you just have to find the cubed root of 64 not the squared root the cubes root of 64 is 4 , positive for because 4*4*4=64, -4*-4*-4=-64
