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4 years ago

If the math Olympiad club consists of 14 students, how many different teams of 5 students can be formed for competitions?

Mathematics

1 answer:

aliina [53]4 years ago

6 0

Answer:

Step-by-step explanation:

5 x 2 = 10

5 x 3 = 15 > 14

therefore...

there are 2 teams of 5

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Solve this system of equations. <br><br> 12x − 18y = 27 <br> 4x − 6y = 10

kifflom [539]

Answer:

no solution

Step-by-step explanation:

12x − 18y = 27

4x − 6y = 10

Multiply the second equation by -3 so we can eliminate x

-3(4x − 6y) = 10*-3

-12x +18y = -30

Add the first equation to this new equation

12x − 18y = 27

-12x +18y = -30

------------------------

0 = -3

This is not a true equation, so there is no solution

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3 years ago

The diagram shown a force being applied forward the right how much Force is being applied

alexandr402 [8]

What diagram is it I needa know t answer

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3 years ago

A 9-pack of plastic cups costs $7.83. What is the unit price?

Illusion [34]

Answer:

0.87$ per unit ........

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3 years ago

Fencing a horse corral carol has 2400 ft of fencing to fence in a rectangular horse corral. (a) find a function that models the

Vanyuwa [196]

Here it is given that the width is x ft and total length of the fence is 2400 ft .

Let the length be y ft

So we have

$2(x+y) =2400
\\
x+y=1200
\\
y = 1200 -x$

Let A represents area, and area is the product of length and width .

So we get

$A = x y$

Substituting the value of y, we will get

$A = x (1200-x)= 1200x -x^2$

Second part

The area is maximum at the vertex, and vertex is

$x = - \frac{1200}{2(-1)} = 600 feet$

And

$y=1200-x = 1200-600 = 600 feet$

And that's the required dimensions .

8 0

3 years ago

The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the

Mrrafil [7]

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7$

8 0

3 years ago